Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 13)
13.
| Reduce | 128352 | to its lowest terms. |
| 238368 |
Answer: Option
Explanation:
128352) 238368 ( 1
128352
---------------
110016 ) 128352 ( 1
110016
------------------
18336 ) 110016 ( 6
110016
-------
x
-------
So, H.C.F. of 128352 and 238368 = 18336.
128352 128352 ÷ 18336 7
Therefore, ------ = -------------- = --
238368 238368 ÷ 18336 13
Discussion:
59 comments Page 6 of 6.
Shravani janadri said:
10 years ago
It can be solved even more efficiently.
Since we have 13 in denominator among options.
238368/13 = 18336.
Now Cross check options to know unit place value.
18336*7=_______2.
18336*5=_______0.
18336*9=_______9.
And the numerator has 2 In units place so go with option 7/13.
This always works if we don't have non of the above as option.
Since we have 13 in denominator among options.
238368/13 = 18336.
Now Cross check options to know unit place value.
18336*7=_______2.
18336*5=_______0.
18336*9=_______9.
And the numerator has 2 In units place so go with option 7/13.
This always works if we don't have non of the above as option.
V!cky said:
10 years ago
391/667.
Guys you try this some from subtraction method you will get wrong answer.
Answer is 17/29. Subtraction method not always give correct answer.
Guys you try this some from subtraction method you will get wrong answer.
Answer is 17/29. Subtraction method not always give correct answer.
:-) said:
10 years ago
I hope it can help,
Let's apply divisibility rule:
Divisibility by 5: Last digit 0 or 5.
Divisibility by 9: Sum of digits = 9 or multiple of 9.
So, as per given numerators of options B and D, these conditions are not satisfied. Hence neither B nor D is answer.
Divisibility by 4: Last two digits 0 or multiple of 4 not being satisfied in option A's denominator. Hence correct option is C.
Let's apply divisibility rule:
Divisibility by 5: Last digit 0 or 5.
Divisibility by 9: Sum of digits = 9 or multiple of 9.
So, as per given numerators of options B and D, these conditions are not satisfied. Hence neither B nor D is answer.
Divisibility by 4: Last two digits 0 or multiple of 4 not being satisfied in option A's denominator. Hence correct option is C.
Royal said:
9 years ago
I think you are wrong, because last two digits of denominator 68 is divisible by 4 and satisfy the divisibility rule. But anyway thanks because it will work at least for some cases.
So can we expect another shortcut here please. And thanks for @Vicky.
So can we expect another shortcut here please. And thanks for @Vicky.
Vip said:
8 years ago
Applying divisibility rule is best to know the answer.
Saloni said:
8 years ago
Is there any easy and quick method to solve this? Please explain me a simple method.
Saloni said:
8 years ago
I also think divisibility rule is easy.
Agree @Vip.
Agree @Vip.
Piyush said:
2 decades ago
Isnt' thr a quicker way tpo find this ans??.. because the answer shown looks to be very time consuming.
Ranjitha said:
8 years ago
Please explain with easy method.
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