Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 13)
13.
Reduce | 128352 | to its lowest terms. |
238368 |
Answer: Option
Explanation:
128352) 238368 ( 1 128352 --------------- 110016 ) 128352 ( 1 110016 ------------------ 18336 ) 110016 ( 6 110016 ------- x ------- So, H.C.F. of 128352 and 238368 = 18336. 128352 128352 ÷ 18336 7 Therefore, ------ = -------------- = -- 238368 238368 ÷ 18336 13
Discussion:
59 comments Page 1 of 6.
A Srihari said:
5 months ago
Guys, Just see the 1st 2 digits of the numerator and denominator it's 12 and 23, which is like their fraction is almost 1/2, so we can directly go for option verification.
>3/4 now way near to 1/2.
>5/13 will be much less than 1/2.
>9/13 is can't be 1/2.
>The only option left is 7/13 .
>3/4 now way near to 1/2.
>5/13 will be much less than 1/2.
>9/13 is can't be 1/2.
>The only option left is 7/13 .
(23)
Neevi said:
11 months ago
128352/238368.
First, we take 128352
Then separate it into 3-digit.
Now find the diff btw 128 & 352 is 224.
224 is divisible by 7.
Follow the same way for 238368.
128 - 352 = 224(it is divisible by 7 and not divisible by 3,5,9)
238 - 368 = 130(it is divisible by 13 and not divisible by 4)
And then the answer is 7/13.
First, we take 128352
Then separate it into 3-digit.
Now find the diff btw 128 & 352 is 224.
224 is divisible by 7.
Follow the same way for 238368.
128 - 352 = 224(it is divisible by 7 and not divisible by 3,5,9)
238 - 368 = 130(it is divisible by 13 and not divisible by 4)
And then the answer is 7/13.
(47)
Yash b said:
12 months ago
Simple divisibility rule;
128352 is divisible by 7, 3
238368 is divisible by 13.
So, option is 7/13.
128352 is divisible by 7, 3
238368 is divisible by 13.
So, option is 7/13.
(18)
Ajay said:
1 year ago
Let's break the fraction.
First, let's take the numerator:
128352=2⁵×3×7×191( prime factorization)--->1
And then now the denominator;
238368 = 2⁵ × 3 × 13 × 191--->2
From 1 and 2,
128352/238368 gives
2⁵ × 3 × 7 × 191/2⁵ × 3 × 13 × 191.
The answer is 7/13 since being all other terms (2⁵,3 and 191) cancelled.
First, let's take the numerator:
128352=2⁵×3×7×191( prime factorization)--->1
And then now the denominator;
238368 = 2⁵ × 3 × 13 × 191--->2
From 1 and 2,
128352/238368 gives
2⁵ × 3 × 7 × 191/2⁵ × 3 × 13 × 191.
The answer is 7/13 since being all other terms (2⁵,3 and 191) cancelled.
(15)
Known said:
1 year ago
Anyone, please explain me in detail to understand the answer.
(6)
Shanmuk Siva Naarappa R said:
1 year ago
Just find the H.C.F. of 128352 & 238368.(Using Division method).
The HCF is 18336.
Now see the last digit of the numerator i.e., '2'. And last digit of HCF is '6'.
If 6*X=_2 i.e., either 6*2=12, or 6*7=42.
So, the numerator is either 2 or 7.
In the given options there is no number with numerator 2, But there is a number with numerator 7. i.e., option (C) 7/13.
The HCF is 18336.
Now see the last digit of the numerator i.e., '2'. And last digit of HCF is '6'.
If 6*X=_2 i.e., either 6*2=12, or 6*7=42.
So, the numerator is either 2 or 7.
In the given options there is no number with numerator 2, But there is a number with numerator 7. i.e., option (C) 7/13.
(14)
Mel said:
2 years ago
@All.
We can Find the unit place by cross-multiplying.
We can Find the unit place by cross-multiplying.
(3)
Jiji said:
2 years ago
First, find the HCF of the numerator and denominator which is 18336, then divide both the numerator and denominator by 18336. Therefore, the answer is 7/13.
(25)
Yogesh khairnar said:
2 years ago
Instead of this go with the options;
1st check only the numerator divide with option A numerator.
Then check for B option with the numerator.
Then check for C option with the numerator.
128352/7 & 238368/13.
If divide you got your answer.
i.e C = 7/13.
1st check only the numerator divide with option A numerator.
Then check for B option with the numerator.
Then check for C option with the numerator.
128352/7 & 238368/13.
If divide you got your answer.
i.e C = 7/13.
(29)
Rashmitha said:
2 years ago
In the options, mostly the denominator is 13.
If we divide 238368 by 13, we can get the exact number which divides both 128352 and 238368.
238368/13=18336 whose last digit is 6.
In 128352 the last digit is 2.
If multiply 6 by 7, then we can get the last digit as 2.
So, the answer is 7/13.
If we divide 238368 by 13, we can get the exact number which divides both 128352 and 238368.
238368/13=18336 whose last digit is 6.
In 128352 the last digit is 2.
If multiply 6 by 7, then we can get the last digit as 2.
So, the answer is 7/13.
(12)
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