Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 1)
1.
Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
Answer: Option
Explanation:
Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.
 |
(4x + 8) = | 5 | (x + 8) |
| 2 |
8x + 16 = 5x + 40
3x = 24
x = 8.
| Hence, required ratio = | (4x + 16) | = | 48 | = 2. |
| (x + 16) | 24 |
Discussion:
319 comments Page 6 of 32.
Gautam Negi said:
1 decade ago
Thanks a lot guys.
Savitha said:
1 decade ago
We already add 8 years....to get the x value then Why we add 16 yrs in second step.
Rohan said:
1 decade ago
Answer to 5/2(x+8) ...in example its is written that After 8 years, he would be two and a half times of Ronit's age
So two and a half is 2 1/2, now 2x2 is 4 and 4+1 is 5 so its 5/2..
So two and a half is 2 1/2, now 2x2 is 4 and 4+1 is 5 so its 5/2..
Cosmicguypradeep said:
1 decade ago
Simple
let the age of the son be "x"
father is aged 3 times more than his son so x+3x=4x
after 8 years,
4x+8=x+8....equation (1)
age will be 2 and half years i.e 2 1/2 = 5/2,
4x+8=5/2(x+8)
==> 8x+16=5x+40
==> x=8
after further 8 years;
4x+8+8=?(x+8+8)
4x+16=?(X+16)
==> ?=4x+16/x+16...equation (2)
==> substitute x=8 in eqution (2),
u will get ?=2
let the age of the son be "x"
father is aged 3 times more than his son so x+3x=4x
after 8 years,
4x+8=x+8....equation (1)
age will be 2 and half years i.e 2 1/2 = 5/2,
4x+8=5/2(x+8)
==> 8x+16=5x+40
==> x=8
after further 8 years;
4x+8+8=?(x+8+8)
4x+16=?(X+16)
==> ?=4x+16/x+16...equation (2)
==> substitute x=8 in eqution (2),
u will get ?=2
Arjun said:
1 decade ago
@Cosmicguypradeep
Let the age of the son be "x"
father is aged 3 times more than his son so x+3x=4x }(i agree this part)
after 8 years,
4x+8=x+8....equation (1)( doubt here q1: how X=4X that is how father age is equal to son age )
Let the age of the son be "x"
father is aged 3 times more than his son so x+3x=4x }(i agree this part)
after 8 years,
4x+8=x+8....equation (1)( doubt here q1: how X=4X that is how father age is equal to son age )
Stella said:
1 decade ago
Thank you friends for your explanations.
Ajay said:
1 decade ago
Can anyone say how the term 5/2(x=8)comes in the 2nd part please ?
Pankaj said:
1 decade ago
As the in statement state that fathers age would be 2 and 1/2 of the ronits ages.
Ronits age is x,
his fathers age is x+3x=4x,
after 8 yaers
(4x+8) = 2*1/2(x+8)
multiply 2*1/2 i.e (2*2+1)/2=5/2
4x+8 =5/2(x+8)
Ronits age is x,
his fathers age is x+3x=4x,
after 8 yaers
(4x+8) = 2*1/2(x+8)
multiply 2*1/2 i.e (2*2+1)/2=5/2
4x+8 =5/2(x+8)
Ashwini said:
1 decade ago
Thanks for explanation.
Shraddha said:
1 decade ago
As in question, fathers age is three times more than son's age. If we take sons age as x than father's age wll 3x how that 4x?
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