Aptitude - Problems on Ages - Discussion

Discussion Forum : Problems on Ages - General Questions (Q.No. 1)
1.
Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
2 times
1 times
2
3 times
4
3 times
Answer: Option
Explanation:

Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.

(4x + 8) = 5 (x + 8)
2

8x + 16 = 5x + 40

3x = 24

x = 8.

Hence, required ratio = (4x + 16) = 48 = 2.
(x + 16) 24

Discussion:
319 comments Page 5 of 32.

Vinod said:   1 decade ago
Thank you vaishu.

Dimple said:   1 decade ago
Acc to me 5/2 multiplied on fathers side?

Pari said:   1 decade ago
Can anyone clear how d equation of(4x+16)/(x+16) is = 48/24

I mean from where these values 48/24 are coming...
plz clarify this point only

Pari said:   1 decade ago
Ohhh got it ...we are to put d value of x i.e 8 in d equation...:)

= (4x+16)/(x+16)
= (4x8+16)/(8x16)
= 48/24
= 2 times
:)

Shivani said:   1 decade ago
How 5/2 come?

Harvinder singh said:   1 decade ago
Two and half mean.. 2+1/2= 2/1+1/2=(2*2+1)/2=(4+1)/2=5/2

Minal said:   1 decade ago
Hi,

See two and half means 2*1/2

So 2*2+1 = 5/2.

Amrutha said:   1 decade ago
Rohit age is x and his father age is 3x ofter 8 years rohit age is 5/2(x+8) and his father age is 3x+8 therefore

3x+8=5/2(x+8)
6x+16=5x+40
x=24

Rohit age is 24 then his father age is 72 year ofter 8 years

It becomes 32 and 80 it is exactly 2 1/2 times of rohit age so answer is 2 times.

Ezhil Arasan SCAD CET said:   1 decade ago
Guess whatz the wrong here:
1st father age is 24 and Rohit age is 8...
atter 8 years: father age is shd b 24+8=32 and Rohit age is 8+8=16...
But in sum itz given after 8 years his age is 2.5 times>then Rohit age... But here 32 nd 16 two times only greater... Why?

Preethi said:   1 decade ago
Thank you vaisu & uttam for your explainations.


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