Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 1)
1.
Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
Answer: Option
Explanation:
Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.
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(4x + 8) = | 5 | (x + 8) |
2 |
8x + 16 = 5x + 40
3x = 24
x = 8.
Hence, required ratio = | (4x + 16) | = | 48 | = 2. |
(x + 16) | 24 |
Discussion:
319 comments Page 25 of 32.
Santhiya said:
7 years ago
@All.
Simply, the solution is;
Given:
Ist father age= 3 times more than son age.
2nd after 8yrs father age= 2 1/2 times more than son age.
3rd after 8 yrs age =2 time more than son age.
Simply, the solution is;
Given:
Ist father age= 3 times more than son age.
2nd after 8yrs father age= 2 1/2 times more than son age.
3rd after 8 yrs age =2 time more than son age.
Sandhiya said:
7 years ago
Given:
Father age = more than 3 times son age.
After 8years = more than 2 1/2 time son age.
After 8 years = more than 2-time son age.
Every 8 years 1/2 times reduced.
Father age = more than 3 times son age.
After 8years = more than 2 1/2 time son age.
After 8 years = more than 2-time son age.
Every 8 years 1/2 times reduced.
(1)
Payal said:
7 years ago
Ronit age = X.
Father age = 3x.
After 8 years.
(X+8) = (3x+8).
Half of of Ronit age.
(X+8) =1/2(3x+8).
X=8.
After further 8 years.
Both age ratio, where X = 8.
(3x+8)/X+8 = 32/16.
=> 2.
Father age = 3x.
After 8 years.
(X+8) = (3x+8).
Half of of Ronit age.
(X+8) =1/2(3x+8).
X=8.
After further 8 years.
Both age ratio, where X = 8.
(3x+8)/X+8 = 32/16.
=> 2.
(1)
Arjun said:
7 years ago
Father age can be taken as x.
Son age is taken as y.
According to the first statement, father age is three times more than sons age at present is x=3y
According to the second statement after 8 years father age is 8 times more than the two and a half age of son age.
2*1/2 can be written as 5/2.
So, x+8=5/2y.
Substitute x=3y,
3y+8=5/2y,
3y-5/2y=-8,
1/2y=-8.
y=-16 after 8 years.
After 8 years father age is twice than son age.
Then after 16 years also twice than son ager.
Son age is taken as y.
According to the first statement, father age is three times more than sons age at present is x=3y
According to the second statement after 8 years father age is 8 times more than the two and a half age of son age.
2*1/2 can be written as 5/2.
So, x+8=5/2y.
Substitute x=3y,
3y+8=5/2y,
3y-5/2y=-8,
1/2y=-8.
y=-16 after 8 years.
After 8 years father age is twice than son age.
Then after 16 years also twice than son ager.
Aiswarya said:
7 years ago
As it is said that father's age is 3 times more than his son's.
So father's present age 3x and son's age x.
After 8 yrs their age will be,
3x+8 = 5/2(x + 8),
3x+8 = ((5x)/2) + (40/2),
2 * (3x+8) = 5x + 40,
6x + 16 = 5x + 40,
x = 24.
So son's age will be 24.
And father's age will be 3x = 72.
Further 8 more years ie; after 16 years,
Son's age will be x+16 ie; = 40,
and father's age will be 3x+16 ie; =88,
Therefore (x+16) ÷ (3+16) = 2.2.
So father's present age 3x and son's age x.
After 8 yrs their age will be,
3x+8 = 5/2(x + 8),
3x+8 = ((5x)/2) + (40/2),
2 * (3x+8) = 5x + 40,
6x + 16 = 5x + 40,
x = 24.
So son's age will be 24.
And father's age will be 3x = 72.
Further 8 more years ie; after 16 years,
Son's age will be x+16 ie; = 40,
and father's age will be 3x+16 ie; =88,
Therefore (x+16) ÷ (3+16) = 2.2.
Ragav said:
7 years ago
Let the age of son be x then age of father will be 4x so we have ratio of father and son equals to 4x:x again after 8 years this becomes 5/2x:x as we all know that difference of age remains same then to make it same multiply above by 2 so that it becomes 5x:2x.
Therefore in 8 years 4x becomes 5x hence x is equal to 8 putting the value we get the age equal to 40 and 16 respectively and after 8 more years it will become 48 and 24 and hence father's age will be twice of the son.
Therefore in 8 years 4x becomes 5x hence x is equal to 8 putting the value we get the age equal to 40 and 16 respectively and after 8 more years it will become 48 and 24 and hence father's age will be twice of the son.
Hafiz Yacir said:
7 years ago
I think 2.5(x+16) = (4x+16).
Neha said:
7 years ago
Son- x father- 3x BUT, it is said MORE than 3 times so x +3x= 4x.
Now, 8 years ahead, son= x+8 and father= 5/2*(x+8).
---> (x+8)=5/2*(x+8),
---> 2(x+8)=5(x+8),
---> 2x + 16= 5x + 40,
---> x= 8 - sons age.
father is 4x= 4*8= 32.
NOW, in total 16 years is asked from the beginning,
So, sons age= 8+16= 24,
Fathers age= 32+16= 48,
48 is 2 times of 24!.
Now, 8 years ahead, son= x+8 and father= 5/2*(x+8).
---> (x+8)=5/2*(x+8),
---> 2(x+8)=5(x+8),
---> 2x + 16= 5x + 40,
---> x= 8 - sons age.
father is 4x= 4*8= 32.
NOW, in total 16 years is asked from the beginning,
So, sons age= 8+16= 24,
Fathers age= 32+16= 48,
48 is 2 times of 24!.
Aman mathur said:
7 years ago
@Amrutha.
The correct answer is 11:5.
Fathers present age :72
Son's present age :24
So ratio:- 3:1
After 8 years:
father's age: 80
son's age: 32
so ratio:- 5:2
Further 8 years after:
Father's age : 88
Son's age: 40
So ratio : 11:5 is the correct answer.
The correct answer is 11:5.
Fathers present age :72
Son's present age :24
So ratio:- 3:1
After 8 years:
father's age: 80
son's age: 32
so ratio:- 5:2
Further 8 years after:
Father's age : 88
Son's age: 40
So ratio : 11:5 is the correct answer.
Shraddha said:
6 years ago
(4x+8) = 5/2(X+8).
= 8x+16 = 5x+40 how it came?
= 8x+16 = 5x+40 how it came?
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