Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 1)
1.
Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
Answer: Option
Explanation:
Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.
 |
(4x + 8) = | 5 | (x + 8) |
| 2 |
8x + 16 = 5x + 40
3x = 24
x = 8.
| Hence, required ratio = | (4x + 16) | = | 48 | = 2. |
| (x + 16) | 24 |
Discussion:
323 comments Page 18 of 33.
Manisha Prasad said:
1 decade ago
Father is aged three times more than his son Ronit = four times of son's age. Is it justified?
Three times more = four times.
HOW can we say this?
Three times more means it could be 3x+1, or 3x+2,.....or five times....it could be anything..
So how can we say three times more = four times.
Three times more = four times.
HOW can we say this?
Three times more means it could be 3x+1, or 3x+2,.....or five times....it could be anything..
So how can we say three times more = four times.
Supriya said:
1 decade ago
It is given in the question that Father is aged three times more than his son Ronit and v have taken Ronit's age as x and father's age as 3x.
Since father age is MORE THAN his son's age it is x+3x.
Since father age is MORE THAN his son's age it is x+3x.
Deepak verma said:
1 decade ago
Why we are taking ratio at end of solution?
Satyam said:
1 decade ago
How the ratio b 4x+16\x+8 ?
It should be 4x+8\x+8 is correct.
It should be 4x+8\x+8 is correct.
Aqeel Sadiq said:
1 decade ago
@Satyam.
Consider a ratio a:b, in x years given ratio will be ax:bx.
After 8 years it will be ax+8:bx+8.
Consider a ratio a:b, in x years given ratio will be ax:bx.
After 8 years it will be ax+8:bx+8.
Haritham said:
1 decade ago
How it is 4x ?
Kinnu said:
1 decade ago
Hey guys I had a simple logic for you.
Father=three times more of his son.
After 8 years father is 2 and a half of his son it means there is a reduce of 1/2.
So for another 8 years there will be a constant reduction of another half i.e; 2 times of his son.
Father=three times more of his son.
After 8 years father is 2 and a half of his son it means there is a reduce of 1/2.
So for another 8 years there will be a constant reduction of another half i.e; 2 times of his son.
Magesh said:
1 decade ago
I am so confused, after I did not get the answer.
Please anyone explain this problem clearly.
Please anyone explain this problem clearly.
Abhi said:
1 decade ago
Nothing to confuse .. Let take sons age as x. Then father age will become 4x as given in question (father's age is three times more than sons age read carefully its not fathers age is three times to sons age.. If three times to sons age means father age will become 3x).
After 8 yrs father age is 2 1/2 of sons age..So,
4x+8 = 2 1/2(x+8).
4x+8 = 5/2(x+8).
2(4x+8) = 5(x+8).
8x+16 = 5x+40.
3x = 24.
x = 8.
After 8 yrs father age is 2 1/2 of sons age..So,
4x+8 = 2 1/2(x+8).
4x+8 = 5/2(x+8).
2(4x+8) = 5(x+8).
8x+16 = 5x+40.
3x = 24.
x = 8.
Harry said:
1 decade ago
Father's age should be 3x and not 4x as some people are saying. It says Father is aged three times more than his son Ronit.
So, it should be x and 3x and not x+3x.
So, it should be x and 3x and not x+3x.
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