Aptitude - Problems on Ages - Discussion

Discussion Forum : Problems on Ages - General Questions (Q.No. 1)
1.
Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
2 times
1 times
2
3 times
4
3 times
Answer: Option
Explanation:

Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.

(4x + 8) = 5 (x + 8)
2

8x + 16 = 5x + 40

3x = 24

x = 8.

Hence, required ratio = (4x + 16) = 48 = 2.
(x + 16) 24

Discussion:
326 comments Page 16 of 33.

Anil said:   1 decade ago
@Poonam And @Thara in question this given that two and half.

Means 2and half which is 2.5 and 5/2 is same equal to 2.5.

Don't get confused in 2/5 and 2.5. Because 2/5 is .4 not 2.5.

ManjulaPriya said:   1 decade ago
2 and a half means 2*1/2 is simplified 2*2=4, and 4+1=5 is come 5/2.

Jyoti Chaudhary said:   1 decade ago
Let Ronit's age = x.

Father's age = x+3x (three times more than his son Ronit) = 4x.

After 8yrs.

Ronit's age = x+8.

Father's age = 4x+8.

But father will be two and a half times of Ronit's age so.

4x+8 = 5/2 (x+8).

x = 8.

Further after 8 years.

Ronit's age = x+8+8 = x+16.

Father's age = 4x+8+8 = 4x+16.

We know the value of x is 8 so putting value of x.

Now,

Ronit's age = x+16=8+16=24.

Father's age = 4x+16 = 4*8 +16 = 32+16 = 48.

Now we will calaulate the ratio of father's to ronit's age.

Father's age/ronit's age = 48/24 = 2.

Thus 2 is answer.

Bharani said:   1 decade ago
@Newbie.

You made a wrong calculation 3*16 = 48 and 52+16 = 68.

Aviskar chapagain said:   1 decade ago
Let,

Father = X.
Ronit = Y.

1st case:
X = 3Y.

2nd case:
X+8 = Y/2.

Third case:
X+16 = Y.

2X+16 = 3Y. From 1st and second case.

Then subtract third case in it. You will get,

X=2Y.

NOOR said:   1 decade ago
Three times parents age of a father is equal to eight time age of his son. Eight years hence the father will twice as old as his son at that time. What are the parent ages?

Can any body solve this question?

Sudipta said:   1 decade ago
Father can't comes to sons age i.e. Father can't come to Ronit's age. Have doubt in?

Mayank varshney said:   1 decade ago
Actually the point is Ronit's father is more than 3 times. So 4x is absolutely right.

Prasanna said:   1 decade ago
Let us assume father age is x.

G. T father age is 3 times greater than rohit age so (x+3x) = 4x.

G. T after 8 years he would be two and half times of ronit's age so 2 (1\2) = 5\2 (2*2+1) /2.

After further 8 years.

(4x+8) = 5/2 (x+8).
8x+16 = 5x+40.
8x-5x = 40-16.
3x = 24.
x = 8.

After further 8 years.
(4x+8) = (x+8).

Add 8 then.

(4x+8+8) = (x+8+8).
(4x+16) = (x+i6).

Required ratio = (4x+16)/(x+16) = 48/24 = 2 (sub x=8).

Rohini said:   1 decade ago
Fathers is aged three times more than his son Ronit.

Assume Ronit's age is x.

Hence fathers age is 3 times more (3x) + in Ronits (x)age,

Which gives, (3x+x) that is 4x.


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