Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 1)
1.
Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
Answer: Option
Explanation:
Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.
 |
(4x + 8) = | 5 | (x + 8) |
| 2 |
8x + 16 = 5x + 40
3x = 24
x = 8.
| Hence, required ratio = | (4x + 16) | = | 48 | = 2. |
| (x + 16) | 24 |
Discussion:
322 comments Page 16 of 33.
NOOR said:
1 decade ago
Three times parents age of a father is equal to eight time age of his son. Eight years hence the father will twice as old as his son at that time. What are the parent ages?
Can any body solve this question?
Can any body solve this question?
Sudipta said:
1 decade ago
Father can't comes to sons age i.e. Father can't come to Ronit's age. Have doubt in?
Mayank varshney said:
1 decade ago
Actually the point is Ronit's father is more than 3 times. So 4x is absolutely right.
Prasanna said:
1 decade ago
Let us assume father age is x.
G. T father age is 3 times greater than rohit age so (x+3x) = 4x.
G. T after 8 years he would be two and half times of ronit's age so 2 (1\2) = 5\2 (2*2+1) /2.
After further 8 years.
(4x+8) = 5/2 (x+8).
8x+16 = 5x+40.
8x-5x = 40-16.
3x = 24.
x = 8.
After further 8 years.
(4x+8) = (x+8).
Add 8 then.
(4x+8+8) = (x+8+8).
(4x+16) = (x+i6).
Required ratio = (4x+16)/(x+16) = 48/24 = 2 (sub x=8).
G. T father age is 3 times greater than rohit age so (x+3x) = 4x.
G. T after 8 years he would be two and half times of ronit's age so 2 (1\2) = 5\2 (2*2+1) /2.
After further 8 years.
(4x+8) = 5/2 (x+8).
8x+16 = 5x+40.
8x-5x = 40-16.
3x = 24.
x = 8.
After further 8 years.
(4x+8) = (x+8).
Add 8 then.
(4x+8+8) = (x+8+8).
(4x+16) = (x+i6).
Required ratio = (4x+16)/(x+16) = 48/24 = 2 (sub x=8).
Rohini said:
1 decade ago
Fathers is aged three times more than his son Ronit.
Assume Ronit's age is x.
Hence fathers age is 3 times more (3x) + in Ronits (x)age,
Which gives, (3x+x) that is 4x.
Assume Ronit's age is x.
Hence fathers age is 3 times more (3x) + in Ronits (x)age,
Which gives, (3x+x) that is 4x.
Rashmi said:
1 decade ago
Hello guys my problem is this why 5/2 is multiplied with (x+8) not with (4x+8). When question is saying father's age would be two and half time of ronit age.
Jyothi sajjan said:
1 decade ago
Hi @Rashmi (4x+8)is cross multiply with 2(denominator)then it becomes 8x+16. and, 5(numerator) is multiplied with (x+8)then it becomes 5x+40 this is the correct manner.
Have a nice day.
Have a nice day.
Darshana said:
1 decade ago
How you got ratio (4x+16)/(x+16) ?
Can you explain the last step of ratio.
Can you explain the last step of ratio.
Chithra said:
1 decade ago
We have 4x+8 = x+8.
Further 8 years means we need to add another 8 on both side,
i.e.. 4x+8+8=x+8+8, which becomes 4x+16=x+16.
We can also write this as (4x+16)/(x+16). Then substitute the value of 8 in that we will get the answer.
Further 8 years means we need to add another 8 on both side,
i.e.. 4x+8+8=x+8+8, which becomes 4x+16=x+16.
We can also write this as (4x+16)/(x+16). Then substitute the value of 8 in that we will get the answer.
Akhila said:
1 decade ago
Why this last step = (4x+8+8)/(x+8+8) should be divisible only?
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