Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 1)
1.
Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
Answer: Option
Explanation:
Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.
 |
(4x + 8) = | 5 | (x + 8) |
| 2 |
8x + 16 = 5x + 40
3x = 24
x = 8.
| Hence, required ratio = | (4x + 16) | = | 48 | = 2. |
| (x + 16) | 24 |
Discussion:
319 comments Page 11 of 32.
Sandhiya said:
7 years ago
Given:
Father age = more than 3 times son age.
After 8years = more than 2 1/2 time son age.
After 8 years = more than 2-time son age.
Every 8 years 1/2 times reduced.
Father age = more than 3 times son age.
After 8years = more than 2 1/2 time son age.
After 8 years = more than 2-time son age.
Every 8 years 1/2 times reduced.
(1)
Petchi Raja said:
2 years ago
Father aged 3 times more than his son Ronit", everyone would think Father's age is triple of Son's age, right?
How to assume this? Anyone, please explain me clearly.
How to assume this? Anyone, please explain me clearly.
(54)
Harry said:
1 decade ago
Father's age should be 3x and not 4x as some people are saying. It says Father is aged three times more than his son Ronit.
So, it should be x and 3x and not x+3x.
So, it should be x and 3x and not x+3x.
Abhinav said:
9 years ago
Please explain.
Father is aged three times more than his son Ronit.
Then why father age = x, and Ronit age is = x?
Why not father age = x? And son Ronit age = y.
Father is aged three times more than his son Ronit.
Then why father age = x, and Ronit age is = x?
Why not father age = x? And son Ronit age = y.
M.Yagya Saini said:
10 years ago
If the age of father is 5 times more then his son. If the sum of the ages is 72 find the age of father and mother?
Ans:- 13=son, father=59. How is that possibly?
Ans:- 13=son, father=59. How is that possibly?
Sajan said:
10 years ago
Son age = x.
Father age = 3x+x.
4x+8 = 2.5 (x+8).
4x+8 = 5/2 (x+8).
2(4x+8) = 5(x+8).
8x+16 = 5x+40.
8x-5x = 40-16.
3x = 24.
x = 8.
Now follow the rest.
Father age = 3x+x.
4x+8 = 2.5 (x+8).
4x+8 = 5/2 (x+8).
2(4x+8) = 5(x+8).
8x+16 = 5x+40.
8x-5x = 40-16.
3x = 24.
x = 8.
Now follow the rest.
Kamesh said:
8 years ago
First, we think Rohit age is x, equation given for after 8 years. And at the end the question is further 8 years it means x+8+8=x+16 same way for father also.
Rashmi said:
1 decade ago
Hello guys my problem is this why 5/2 is multiplied with (x+8) not with (4x+8). When question is saying father's age would be two and half time of ronit age.
Kamleshkumar said:
2 years ago
Say Sons age is X;
F = 3X
3X + 8 = 5/2(X+8).
6X + 16 = 5X+40.
X = 40 - 16,
X = 24.
So, 3X+16/X+16.
= 3 * 24+16/24+16.
= 88/40.
= 2.2.
Means -> 2 1/5.
F = 3X
3X + 8 = 5/2(X+8).
6X + 16 = 5X+40.
X = 40 - 16,
X = 24.
So, 3X+16/X+16.
= 3 * 24+16/24+16.
= 88/40.
= 2.2.
Means -> 2 1/5.
(18)
Sandhya said:
1 decade ago
Aafreen Rah:
Its 3x+x because "Father's age is 3 times (3x) more than (+) his son's age (x)". Here son's age is "x" so just add "x" age to 3times (3x).
Its 3x+x because "Father's age is 3 times (3x) more than (+) his son's age (x)". Here son's age is "x" so just add "x" age to 3times (3x).
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