Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 2)
2.
The sum of ages of 5 children born at the intervals of 3 years each is 50 years. What is the age of the youngest child?
Answer: Option
Explanation:
Let the ages of children be x, (x + 3), (x + 6), (x + 9) and (x + 12) years.
Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50
5x = 20
x = 4.
Age of the youngest child = x = 4 years.
Discussion:
102 comments Page 8 of 11.
Karthika said:
9 years ago
Let the ages be,
X-6, x-3, x, x+3, x+6
5x=50
X=10
Youngest =10 - 6= 4.
X-6, x-3, x, x+3, x+6
5x=50
X=10
Youngest =10 - 6= 4.
Prakash said:
4 years ago
How you taken x+3, 6, 9, 12?
Instead we can take x+1, x+2, x+3, x+4, x+5.
Instead we can take x+1, x+2, x+3, x+4, x+5.
(1)
MATHAN said:
10 years ago
5x + (3 + 6 + 9 + 12) = 50.
5x + 30 = 50.
5x = 50 - 30.
5x = 20.
x = 4.
5x + 30 = 50.
5x = 50 - 30.
5x = 20.
x = 4.
(1)
Jawahir Saly said:
4 years ago
3rd person age is = 50/5 = 10.
So, age of 1st person = 10 - 6 = 4 years.
So, age of 1st person = 10 - 6 = 4 years.
(7)
Chandra said:
4 years ago
(A)+(A+3)+(A+6)+(A+9)+(A+12) =>5A+30.
=> 5A+30 = 50.
=> A = 4.
=> 5A+30 = 50.
=> A = 4.
(15)
Shyam raj said:
8 years ago
How can we say that answer(4yrs) is the age of last younger one?
Sravani said:
6 years ago
How you took that values x, x+3, x+6, x+9, x+12.
Please reply.
Please reply.
Gkgokulan said:
1 decade ago
Its simple logic frnds 4+7+10+13+16=50.
Then the answer is 4.
Then the answer is 4.
Nandish said:
2 decades ago
x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50
how 50 come
how 50 come
Suresh.neelikonda said:
1 decade ago
x+(x+3)+(x+6)+(x+9)+(x+12) = 50.
5x+30 = 50.
5x = 20.
x = 4.
5x+30 = 50.
5x = 20.
x = 4.
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