IndiaBIX

Aptitude - Problems on Ages - Discussion

Discussion Forum : Problems on Ages - General Questions (Q.No. 2)
Problems on Ages
2.
The sum of ages of 5 children born at the intervals of 3 years each is 50 years. What is the age of the youngest child?
4 years
8 years
10 years
None of these
Answer: Option
Explanation:

Let the ages of children be x, (x + 3), (x + 6), (x + 9) and (x + 12) years.

Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50

5x = 20

x = 4.

Age of the youngest child = x = 4 years.

Discussion:
99 comments Page 8 of 10.
MATHAN said:   9 years ago
5x + (3 + 6 + 9 + 12) = 50.

5x + 30 = 50.
5x = 50 - 30.
5x = 20.

x = 4.
(1)
Chandra said:   3 years ago
(A)+(A+3)+(A+6)+(A+9)+(A+12) =>5A+30.
=> 5A+30 = 50.
=> A = 4.
(15)
Shyam raj said:   8 years ago
How can we say that answer(4yrs) is the age of last younger one?
Sravani said:   6 years ago
How you took that values x, x+3, x+6, x+9, x+12.

Please reply.
Gkgokulan said:   1 decade ago
Its simple logic frnds 4+7+10+13+16=50.

Then the answer is 4.
Nandish said:   1 decade ago
x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50


how 50 come
Suresh.neelikonda said:   1 decade ago
x+(x+3)+(x+6)+(x+9)+(x+12) = 50.
5x+30 = 50.
5x = 20.
x = 4.
Adittya said:   10 years ago
How can we get the age of the middle one or the oldest one?
ASWIN BHASKAR said:   1 decade ago
X, X+3, X+6, X+9, X+12=50
5X = 50-30.
5X = 20.
X = 4.
Martin said:   2 decades ago
x+3+x+6+x+9+x+12=30

5x+30=50

5x=50-30

5x=20

x=4.
(1)
Post your comments here:

Your comments will be displayed after verification.

Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers