# Aptitude - Problems on Ages - Discussion

Discussion Forum : Problems on Ages - General Questions (Q.No. 2)

2.

The sum of ages of 5 children born at the intervals of 3 years each is 50 years. What is the age of the youngest child?

Answer: Option

Explanation:

Let the ages of children be *x*, (*x* + 3), (*x* + 6), (*x* + 9) and (*x* + 12) years.

Then, *x* + (*x* + 3) + (*x* + 6) + (*x* + 9) + (*x* + 12) = 50

5*x* = 20

*x* = 4.

Age of the youngest child = *x* = 4 years.

Discussion:

91 comments Page 1 of 10.
Alisha Mugale said:
2 months ago

Consider A, B, C, D, E are 5 children.

Let the lowest value as 4 for the youngest child.

Start from 4 and add the difference of 3 to each value.

4 + 7+ 10+ 13+ 16 = 50.

Let the lowest value as 4 for the youngest child.

Start from 4 and add the difference of 3 to each value.

4 + 7+ 10+ 13+ 16 = 50.

(7)

Arpitha said:
2 months ago

Here, How come 30? Please explain me.

(2)

Gopinath said:
2 months ago

First, you notice every 5 children birth in 3 years cap in 50 years what's is the age in the youngest child.

X, (x+3), (x+6), (x+9), (x+12) years.

x+(x+3)+(x+6)+(x+9)+(x+12) = 50.

Then, here it's using the method in adding x in out 5X +30 = 50.

5X= 50-30.

5X= 20, divisible by 5,

X= 4.

X, (x+3), (x+6), (x+9), (x+12) years.

x+(x+3)+(x+6)+(x+9)+(x+12) = 50.

Then, here it's using the method in adding x in out 5X +30 = 50.

5X= 50-30.

5X= 20, divisible by 5,

X= 4.

(9)

Chandra said:
8 months ago

(A)+(A+3)+(A+6)+(A+9)+(A+12) =>5A+30.

=> 5A+30 = 50.

=> A = 4.

=> 5A+30 = 50.

=> A = 4.

(4)

Jawahir Saly said:
9 months ago

3rd person age is = 50/5 = 10.

So, age of 1st person = 10 - 6 = 4 years.

So, age of 1st person = 10 - 6 = 4 years.

Prakash said:
11 months ago

How you taken x+3, 6, 9, 12?

Instead we can take x+1, x+2, x+3, x+4, x+5.

Instead we can take x+1, x+2, x+3, x+4, x+5.

Hari said:
1 year ago

bro here 50 means?

Hari said:
1 year ago

What 50 indicates here? Please explain.

(1)

M.Manimaran said:
2 years ago

Thank you for the formula @Raj.

Ashu said:
2 years ago

Can anyone explain me this again?

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