Aptitude - Problems on Ages - Discussion

Discussion Forum : Problems on Ages - General Questions (Q.No. 2)
2.
The sum of ages of 5 children born at the intervals of 3 years each is 50 years. What is the age of the youngest child?
4 years
8 years
10 years
None of these
Answer: Option
Explanation:

Let the ages of children be x, (x + 3), (x + 6), (x + 9) and (x + 12) years.

Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50

5x = 20

x = 4.

Age of the youngest child = x = 4 years.

Discussion:
91 comments Page 1 of 10.

Alisha Mugale said:   2 months ago
Consider A, B, C, D, E are 5 children.

Let the lowest value as 4 for the youngest child.

Start from 4 and add the difference of 3 to each value.
4 + 7+ 10+ 13+ 16 = 50.
(7)

Arpitha said:   2 months ago
Here, How come 30? Please explain me.
(2)

Gopinath said:   2 months ago
First, you notice every 5 children birth in 3 years cap in 50 years what's is the age in the youngest child.

X, (x+3), (x+6), (x+9), (x+12) years.
x+(x+3)+(x+6)+(x+9)+(x+12) = 50.
Then, here it's using the method in adding x in out 5X +30 = 50.
5X= 50-30.
5X= 20, divisible by 5,
X= 4.
(9)

Chandra said:   8 months ago
(A)+(A+3)+(A+6)+(A+9)+(A+12) =>5A+30.
=> 5A+30 = 50.
=> A = 4.
(4)

Jawahir Saly said:   9 months ago
3rd person age is = 50/5 = 10.
So, age of 1st person = 10 - 6 = 4 years.

Prakash said:   11 months ago
How you taken x+3, 6, 9, 12?

Instead we can take x+1, x+2, x+3, x+4, x+5.

Hari said:   1 year ago
bro here 50 means?

Hari said:   1 year ago
What 50 indicates here? Please explain.
(1)

M.Manimaran said:   2 years ago
Thank you for the formula @Raj.

Ashu said:   2 years ago
Can anyone explain me this again?


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