Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 2)
2.
The sum of ages of 5 children born at the intervals of 3 years each is 50 years. What is the age of the youngest child?
Answer: Option
Explanation:
Let the ages of children be x, (x + 3), (x + 6), (x + 9) and (x + 12) years.
Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50
5x = 20
x = 4.
Age of the youngest child = x = 4 years.
Discussion:
102 comments Page 2 of 11.
Raju Sampang Ample said:
3 years ago
Let the X be the first or Oldest Child born to Uncle “Bhokal”.
Since All the child is born at 3 years later than their elder Siblings
Therefore sequence will be
X( eldest Child)
X-3
X-6
X-9
X-12( youngest Child)
So, finding X value does not mean the youngest child rather it’s the age of the eldest child
Now, as per the question,
Total age of Children = 50
X+X-3+X-6+X-9+X-12=50
Total X’s + Total Numbers= 50
5X-30=50
5X= 50+30
X=80/5
X=16 (Eldest Son Age)
Since Youngest Child came 12 years later than his /her eldest sibling.
So youngest child= X-12= 16-12=4 years
Since All the child is born at 3 years later than their elder Siblings
Therefore sequence will be
X( eldest Child)
X-3
X-6
X-9
X-12( youngest Child)
So, finding X value does not mean the youngest child rather it’s the age of the eldest child
Now, as per the question,
Total age of Children = 50
X+X-3+X-6+X-9+X-12=50
Total X’s + Total Numbers= 50
5X-30=50
5X= 50+30
X=80/5
X=16 (Eldest Son Age)
Since Youngest Child came 12 years later than his /her eldest sibling.
So youngest child= X-12= 16-12=4 years
(11)
Alisha Mugale said:
3 years ago
Consider A, B, C, D, E are 5 children.
Let the lowest value as 4 for the youngest child.
Start from 4 and add the difference of 3 to each value.
4 + 7+ 10+ 13+ 16 = 50.
Let the lowest value as 4 for the youngest child.
Start from 4 and add the difference of 3 to each value.
4 + 7+ 10+ 13+ 16 = 50.
(38)
Arpitha said:
3 years ago
Here, How come 30? Please explain me.
(10)
Gopinath said:
3 years ago
First, you notice every 5 children birth in 3 years cap in 50 years what's is the age in the youngest child.
X, (x+3), (x+6), (x+9), (x+12) years.
x+(x+3)+(x+6)+(x+9)+(x+12) = 50.
Then, here it's using the method in adding x in out 5X +30 = 50.
5X= 50-30.
5X= 20, divisible by 5,
X= 4.
X, (x+3), (x+6), (x+9), (x+12) years.
x+(x+3)+(x+6)+(x+9)+(x+12) = 50.
Then, here it's using the method in adding x in out 5X +30 = 50.
5X= 50-30.
5X= 20, divisible by 5,
X= 4.
(29)
Chandra said:
4 years ago
(A)+(A+3)+(A+6)+(A+9)+(A+12) =>5A+30.
=> 5A+30 = 50.
=> A = 4.
=> 5A+30 = 50.
=> A = 4.
(15)
Jawahir Saly said:
4 years ago
3rd person age is = 50/5 = 10.
So, age of 1st person = 10 - 6 = 4 years.
So, age of 1st person = 10 - 6 = 4 years.
(7)
Prakash said:
4 years ago
How you taken x+3, 6, 9, 12?
Instead we can take x+1, x+2, x+3, x+4, x+5.
Instead we can take x+1, x+2, x+3, x+4, x+5.
(1)
Hari said:
4 years ago
bro here 50 means?
Hari said:
4 years ago
What 50 indicates here? Please explain.
(1)
M.Manimaran said:
5 years ago
Thank you for the formula @Raj.
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