Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 2)
2.
The sum of ages of 5 children born at the intervals of 3 years each is 50 years. What is the age of the youngest child?
Answer: Option
Explanation:
Let the ages of children be x, (x + 3), (x + 6), (x + 9) and (x + 12) years.
Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50
5x = 20
x = 4.
Age of the youngest child = x = 4 years.
Discussion:
99 comments Page 3 of 10.
Sravani said:
6 years ago
How you took that values x, x+3, x+6, x+9, x+12.
Please reply.
Please reply.
Sonam said:
6 years ago
Can anyone help me to solve this?
A Father's age is 30 years older than the youngest son Tashi. Dema is 2 years older than Tashi. Sangay is 3 years older than Dema. The sum of the ages of the the children are 52. How old is the father?
A Father's age is 30 years older than the youngest son Tashi. Dema is 2 years older than Tashi. Sangay is 3 years older than Dema. The sum of the ages of the the children are 52. How old is the father?
Anupama said:
6 years ago
If I take 1+4+7+10+13 = 35.
35x = 50.
Then the youngest child is 50/35, is it a wrong method?
35x = 50.
Then the youngest child is 50/35, is it a wrong method?
MOSES AHIMBISIBWE said:
6 years ago
The answer is 4, because if you get 4+7+10+13-16 =50. Following their 3 years interval. Therefore, 4 is correct.
Chekuthan said:
6 years ago
@Sudheer.
It is right. x= 16. So, younger ones age will be (x-12), which is 4.
Hence the answer.
It is right. x= 16. So, younger ones age will be (x-12), which is 4.
Hence the answer.
Devakshi said:
7 years ago
x+(x+3)+(x+6)+(x+9)+(x+12)=50.
5x+30=50,
5x=50-30,
5x=20,
x=20/5,
x=4.
Ans=4.
5x+30=50,
5x=50-30,
5x=20,
x=20/5,
x=4.
Ans=4.
Vikram said:
7 years ago
Divide the sum of the ages by total no of children 50/5=10.
Now as we know that the age varies by 3 years...so take 10+3 &10-3=13&7.
then again take the age and sub and add 3. i.e; 13+3&7-3=16&4,
Now add all the operations 4 + 7 + 10 + 13 + 16 = 50.
Now as we know that the age varies by 3 years...so take 10+3 &10-3=13&7.
then again take the age and sub and add 3. i.e; 13+3&7-3=16&4,
Now add all the operations 4 + 7 + 10 + 13 + 16 = 50.
Akhil said:
7 years ago
According to me;
The youngest children age = x+12.
= 4+12.
= 16.
The youngest children age = x+12.
= 4+12.
= 16.
Malak said:
7 years ago
The sum of age of 3 sisters now is 25 years. If the oldest was born before the middle by 3 years and the middle was born before the youngest by two years. Find the age of each of them.
Please, anyone, answer it.
Please, anyone, answer it.
Shyam raj said:
8 years ago
How can we say that answer(4yrs) is the age of last younger one?
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