Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 2)
2.
The sum of ages of 5 children born at the intervals of 3 years each is 50 years. What is the age of the youngest child?
Answer: Option
Explanation:
Let the ages of children be x, (x + 3), (x + 6), (x + 9) and (x + 12) years.
Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50
5x = 20
x = 4.
Age of the youngest child = x = 4 years.
Discussion:
102 comments Page 4 of 11.
Akhil said:
8 years ago
According to me;
The youngest children age = x+12.
= 4+12.
= 16.
The youngest children age = x+12.
= 4+12.
= 16.
Malak said:
8 years ago
The sum of age of 3 sisters now is 25 years. If the oldest was born before the middle by 3 years and the middle was born before the youngest by two years. Find the age of each of them.
Please, anyone, answer it.
Please, anyone, answer it.
Shyam raj said:
8 years ago
How can we say that answer(4yrs) is the age of last younger one?
Kanwal said:
8 years ago
How we get 5 in this?
Pramod ( nepal) said:
8 years ago
@Pooja,
According to your Q 1st eq x+ (x+5) + (x+10) but if after 5 years.
The sum of there age 60 the new eq become (x-5) +x+ (x+5) = 60.
After solving x=20.
Youngest bro age is 15 but 5 years ago his age is 10.
According to your Q 1st eq x+ (x+5) + (x+10) but if after 5 years.
The sum of there age 60 the new eq become (x-5) +x+ (x+5) = 60.
After solving x=20.
Youngest bro age is 15 but 5 years ago his age is 10.
Srini said:
9 years ago
Youngest child means x+12 is the youngest one rite?
Karthika said:
9 years ago
Let the ages be,
X-6, x-3, x, x+3, x+6
5x=50
X=10
Youngest =10 - 6= 4.
X-6, x-3, x, x+3, x+6
5x=50
X=10
Youngest =10 - 6= 4.
Baby Jhie said:
9 years ago
Children age+interval 3
5 ---> x
4 ---> x+3
3 ---> (x+3+3)=x+6.
2 ---> (x+6+3)=x+9.
1 ---> (x+9+3)=x+12.
Sum of their age is 50.
x+x+3+x+6+x+9+x+12=50.
5x+30=50,
5x=50-30,
5x=20,
5x=20,
----------
5
x=4.
Let's check:
Eldest (1) (x+12)--4+12=16
Next (2) (x+9)--4+9=13
Third(3) (x+6)--4+6=10
Fourth(4) (x+3)--4+3=7
Youngest(5) (x)--4
Take note:
There is an interval of 3 years.
5 ---> x
4 ---> x+3
3 ---> (x+3+3)=x+6.
2 ---> (x+6+3)=x+9.
1 ---> (x+9+3)=x+12.
Sum of their age is 50.
x+x+3+x+6+x+9+x+12=50.
5x+30=50,
5x=50-30,
5x=20,
5x=20,
----------
5
x=4.
Let's check:
Eldest (1) (x+12)--4+12=16
Next (2) (x+9)--4+9=13
Third(3) (x+6)--4+6=10
Fourth(4) (x+3)--4+3=7
Youngest(5) (x)--4
Take note:
There is an interval of 3 years.
Suriya khumar said:
9 years ago
HI guys.
First see the option.
In the question, they said that difference between the children is 3 years, and the total age is 50 years.
Hence,
Option A.
4+7+10+13+16 = 50 thats all.
Have a nice day!
First see the option.
In the question, they said that difference between the children is 3 years, and the total age is 50 years.
Hence,
Option A.
4+7+10+13+16 = 50 thats all.
Have a nice day!
Raquel said:
9 years ago
Step 1:Let x be the age of the youngest,
Step 2. Write out the equation,
x + (x+5) + (x+10)= 60,
Step 3: Isolate the variable x,
x+x+x+5+10=60,
3x+ 15 = 60,
3x= 60-15,
3x = 45,
x = 15 (present age of the youngest),
To find the age of the youngest five years ago we can use this expression ,
(x-5). Therefore, the age of the youngest five years ago is 10, since 15-5=10.
Step 2. Write out the equation,
x + (x+5) + (x+10)= 60,
Step 3: Isolate the variable x,
x+x+x+5+10=60,
3x+ 15 = 60,
3x= 60-15,
3x = 45,
x = 15 (present age of the youngest),
To find the age of the youngest five years ago we can use this expression ,
(x-5). Therefore, the age of the youngest five years ago is 10, since 15-5=10.
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