Aptitude - Problems on Ages - Discussion

Discussion Forum : Problems on Ages - General Questions (Q.No. 2)
2.
The sum of ages of 5 children born at the intervals of 3 years each is 50 years. What is the age of the youngest child?
4 years
8 years
10 years
None of these
Answer: Option
Explanation:

Let the ages of children be x, (x + 3), (x + 6), (x + 9) and (x + 12) years.

Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50

5x = 20

x = 4.

Age of the youngest child = x = 4 years.

Discussion:
99 comments Page 4 of 10.

Kanwal said:   8 years ago
How we get 5 in this?

Pramod ( nepal) said:   8 years ago
@Pooja,

According to your Q 1st eq x+ (x+5) + (x+10) but if after 5 years.

The sum of there age 60 the new eq become (x-5) +x+ (x+5) = 60.

After solving x=20.

Youngest bro age is 15 but 5 years ago his age is 10.

Srini said:   8 years ago
Youngest child means x+12 is the youngest one rite?

Karthika said:   8 years ago
Let the ages be,

X-6, x-3, x, x+3, x+6
5x=50
X=10
Youngest =10 - 6= 4.

Baby Jhie said:   8 years ago
Children age+interval 3
5 ---> x
4 ---> x+3
3 ---> (x+3+3)=x+6.
2 ---> (x+6+3)=x+9.
1 ---> (x+9+3)=x+12.

Sum of their age is 50.
x+x+3+x+6+x+9+x+12=50.
5x+30=50,
5x=50-30,
5x=20,
5x=20,
----------
5
x=4.

Let's check:

Eldest (1) (x+12)--4+12=16
Next (2) (x+9)--4+9=13
Third(3) (x+6)--4+6=10
Fourth(4) (x+3)--4+3=7
Youngest(5) (x)--4

Take note:
There is an interval of 3 years.

Suriya khumar said:   8 years ago
HI guys.

First see the option.

In the question, they said that difference between the children is 3 years, and the total age is 50 years.

Hence,

Option A.

4+7+10+13+16 = 50 thats all.

Have a nice day!

Raquel said:   8 years ago
Step 1:Let x be the age of the youngest,
Step 2. Write out the equation,
x + (x+5) + (x+10)= 60,
Step 3: Isolate the variable x,
x+x+x+5+10=60,
3x+ 15 = 60,
3x= 60-15,
3x = 45,
x = 15 (present age of the youngest),

To find the age of the youngest five years ago we can use this expression ,
(x-5). Therefore, the age of the youngest five years ago is 10, since 15-5=10.

Pooja said:   8 years ago
A man had three sons and they were born at an interval of five years. The sum of their ages after 5years will be 60 years. What was the age of youngest son five years ago?

Can anyone solve this?

Ganesh mudaliyar said:   8 years ago
There is a slight change they should have mention let the youngest child be x.

Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50,
5x = 20,
x = 4.

Age of the youngest child = x = 4 years.

Shawon said:   9 years ago
Can anybody solve the problem? Please.

Three times the present age of a father is equal to eight times the present of his son. Eight years hence the father will twice as old as his son at that time. What are their present age?


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