Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 2)
2.
The sum of ages of 5 children born at the intervals of 3 years each is 50 years. What is the age of the youngest child?
Answer: Option
Explanation:
Let the ages of children be x, (x + 3), (x + 6), (x + 9) and (x + 12) years.
Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50
5x = 20
x = 4.
Age of the youngest child = x = 4 years.
Discussion:
99 comments Page 9 of 10.
Aravind said:
1 decade ago
Here youngest means the smaller (4x), why we took x?
Aarthi said:
1 decade ago
X+12+x+9+x+6+x+3+x=50.
5x+30=50.
(x+6) =10.
X=4.
5x+30=50.
(x+6) =10.
X=4.
Srini said:
8 years ago
Youngest child means x+12 is the youngest one rite?
Sangeetha said:
1 decade ago
Thank you ishu subham, very simple and good logic.
Priya said:
2 decades ago
How to form this step : x+3+x+6+x+9+x+12 ?
Rinshan said:
1 decade ago
4x mean 4 times of the youngest ones age.
Hari said:
4 years ago
What 50 indicates here? Please explain.
(1)
Nikhil said:
9 years ago
How we get x + 12?
Explain this step.
Explain this step.
Arun said:
10 years ago
Is there any short cut method please?
Arpitha said:
3 years ago
Here, How come 30? Please explain me.
(10)
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