Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 2)
2.
The sum of ages of 5 children born at the intervals of 3 years each is 50 years. What is the age of the youngest child?
Answer: Option
Explanation:
Let the ages of children be x, (x + 3), (x + 6), (x + 9) and (x + 12) years.
Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50
5x = 20
x = 4.
Age of the youngest child = x = 4 years.
Discussion:
99 comments Page 7 of 10.
Anupama said:
6 years ago
If I take 1+4+7+10+13 = 35.
35x = 50.
Then the youngest child is 50/35, is it a wrong method?
35x = 50.
Then the youngest child is 50/35, is it a wrong method?
Gyan said:
2 decades ago
Jus Add x+0
X+3
X+6
X+9
X+12
X+3
X+6
X+9
X+12
Sairam said:
1 decade ago
(x+2),(x+4),(x+6),(x+8),(x+10).
Total: x+2+x+4+x+6+x+8+x+10 = 50.
5x+30=50
5x=20
x=4.
Total: x+2+x+4+x+6+x+8+x+10 = 50.
5x+30=50
5x=20
x=4.
Giri said:
2 years ago
Total sum 50.
Total children 5.
So, 50/5 =10.
Interval each 3,
So, the youngest age 4.
Total children 5.
So, 50/5 =10.
Interval each 3,
So, the youngest age 4.
(11)
Rupesh said:
10 years ago
Can any one, who has in depth knowledge in this can give the age of 3rd person?
Zeekut said:
1 decade ago
x+3+x+6+x+9+x+12+x = 50.
5x+30 = 50.
5x = 50-30.
5x = 20.
x = 20/5.
x = 4.
5x+30 = 50.
5x = 50-30.
5x = 20.
x = 20/5.
x = 4.
Devakshi said:
7 years ago
x+(x+3)+(x+6)+(x+9)+(x+12)=50.
5x+30=50,
5x=50-30,
5x=20,
x=20/5,
x=4.
Ans=4.
5x+30=50,
5x=50-30,
5x=20,
x=20/5,
x=4.
Ans=4.
Karthika said:
8 years ago
Let the ages be,
X-6, x-3, x, x+3, x+6
5x=50
X=10
Youngest =10 - 6= 4.
X-6, x-3, x, x+3, x+6
5x=50
X=10
Youngest =10 - 6= 4.
Prakash said:
3 years ago
How you taken x+3, 6, 9, 12?
Instead we can take x+1, x+2, x+3, x+4, x+5.
Instead we can take x+1, x+2, x+3, x+4, x+5.
(1)
Jawahir Saly said:
3 years ago
3rd person age is = 50/5 = 10.
So, age of 1st person = 10 - 6 = 4 years.
So, age of 1st person = 10 - 6 = 4 years.
(7)
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