Aptitude - Problems on Ages - Discussion

Discussion Forum : Problems on Ages - General Questions (Q.No. 2)
2.
The sum of ages of 5 children born at the intervals of 3 years each is 50 years. What is the age of the youngest child?
4 years
8 years
10 years
None of these
Answer: Option
Explanation:

Let the ages of children be x, (x + 3), (x + 6), (x + 9) and (x + 12) years.

Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50

5x = 20

x = 4.

Age of the youngest child = x = 4 years.

Discussion:
102 comments Page 6 of 11.

Basavaraj Marapur said:   1 decade ago
Take youngest child = x.

So, (x-12) + (x-9) + (x-6) + (x-3) + x = 50.

5x-30 = 50;

5x = 20;

x = 4.

So youngest child is ---> 20;

Sudheer said:   1 decade ago
Let x+(x-3)+(x-6)+(x-9)+(x-12)=50
5x-30=50
5x=80
x=16
is this correct or not?
if it is wrong then explain the reason..

Ishu Subham said:   1 decade ago
Let the ages be (x-6), (x-3), (x), (x+3), (x+6).
then sum of ages = 5x
=> 5x = 50
x = 10
youngest = x-6
=4

Prasanna said:   10 years ago
Average/total number.

A + B + C + D + E/5 = 50.
50/5 = 10.
C = 10.
10 - 3 = 7.

7 - 3 = 4 -> YOUNGEST ONE'S AGE IS 4yrs.

Satheesh said:   1 decade ago
It seems these calculation are merely mathematical wise not logic wise. Whats the relation between X and younger child?

NANDAN said:   2 decades ago
If 1st child age x then 3year gap for next child so x+3
5 children = 5x
5x+30=50
5x=50-30
5x=20
x=20/5
x=4
so 4 years

Mahesh said:   1 decade ago
In the question its mentioned that "the intervals of 3 years each is 50 years" it means each child having 50 rit.

MOSES AHIMBISIBWE said:   7 years ago
The answer is 4, because if you get 4+7+10+13-16 =50. Following their 3 years interval. Therefore, 4 is correct.

Srujan said:   1 decade ago
@kumuda sub x value in all then u will get 4,7,10,13,16.

So among them d least age is 4 i.e younger one.

Cherry said:   2 decades ago
x+3x+6x+9x+12x=50

x(1+3+6+9+12)=50

x=50/31

x=1.64

If we do the same like this what is that x mean?


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