Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 8)
8.
The sum of the present ages of a father and his son is 60 years. Six years ago, father's age was five times the age of the son. After 6 years, son's age will be:
Answer: Option
Explanation:
Let the present ages of son and father be x and (60 -x) years respectively.
Then, (60 - x) - 6 = 5(x - 6)
54 - x = 5x - 30
6x = 84
x = 14.
Son's age after 6 years = (x+ 6) = 20 years..
Discussion:
71 comments Page 6 of 8.
Sunil said:
1 decade ago
Fathers age 4 times of his son means.
Sons age X.
Fathers age 4x.
Or
Sons age 4x.
Fathers age x.
Which one is right ? How to solve explain ?
Sons age X.
Fathers age 4x.
Or
Sons age 4x.
Fathers age x.
Which one is right ? How to solve explain ?
Rass said:
8 years ago
The age of A and B three years ago were 'x' and 'y+2' years, therefore the sum of their ages 4 years hence will be?
Can someone solve this?
Can someone solve this?
Yakesh said:
1 decade ago
Before(6 years back): 5x, x
Present:5x+6, x+6
After 6 years:5x+12,x+12
and 5x+6+x+6=60
x=8
after 6 years = x+12 = 8+12 = 20.
Present:5x+6, x+6
After 6 years:5x+12,x+12
and 5x+6+x+6=60
x=8
after 6 years = x+12 = 8+12 = 20.
Avinash said:
1 decade ago
In previous sum + for ago in this this sum your using - for ago what we have to use say properly.
Rohan magar said:
1 decade ago
@Amit thanks yar. Your method is easy and simple to understand :).
Sirisha said:
1 decade ago
@santosh
Amit is right. He taking as ago, present, after.
Amit is right. He taking as ago, present, after.
Shaila said:
8 years ago
Thank you everyone for explaining the solution.
Gaurav kumar said:
6 years ago
Thank you so much for explaining the answer.
Hassan said:
5 years ago
Very helpful. Thanks for explaining @Amit.
(1)
Shoeb said:
1 decade ago
Thank for making this sum so simple....
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