Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 8)
8.
The sum of the present ages of a father and his son is 60 years. Six years ago, father's age was five times the age of the son. After 6 years, son's age will be:
Answer: Option
Explanation:
Let the present ages of son and father be x and (60 -x) years respectively.
Then, (60 - x) - 6 = 5(x - 6)
54 - x = 5x - 30
6x = 84
x = 14.
Son's age after 6 years = (x+ 6) = 20 years..
Discussion:
71 comments Page 5 of 8.
Pandi said:
1 decade ago
Now son age x and father age is y
then
x+y=60---->1
six years before son=x-6, father=5(x-6)
so
y-6=5(x-6)
y-6=5x-30
5x-y=24--->2
solve 1 and
get x=14
x is present age
after six years x+6=20
then
x+y=60---->1
six years before son=x-6, father=5(x-6)
so
y-6=5(x-6)
y-6=5x-30
5x-y=24--->2
solve 1 and
get x=14
x is present age
after six years x+6=20
Siva said:
10 years ago
6 years ago son age = x, then father = 5x.
Present age of son means x+6 like that father age is 5x+6.
x+6+5x+6 = 60. So x = 8, here it is.
After 6 years son age will be x+6+6 = 8+6+6 = 20.
Present age of son means x+6 like that father age is 5x+6.
x+6+5x+6 = 60. So x = 8, here it is.
After 6 years son age will be x+6+6 = 8+6+6 = 20.
Kirti said:
10 years ago
Father age = f, son age = s.
Then f+s = 60;
f+6 = 5(s+6).
On solving s = 6;
Then present age of son = s+6 = 6+6 = 12;
Then after 6 years it will be = 12+6 = 18;
What is wrong in that?
Then f+s = 60;
f+6 = 5(s+6).
On solving s = 6;
Then present age of son = s+6 = 6+6 = 12;
Then after 6 years it will be = 12+6 = 18;
What is wrong in that?
Prithiv raj said:
6 years ago
Let father age be x.
Son be y.
X+y=60,
X-6=5y,
Y=x-6/5.
Sub y in above eq.
X+x-6/5=60.
5x+x-6=300.
6x=294.
X=49 father age.
Sub x in above.
49+y=60.
Y=11.
After 6 years 11+6=17 years.
Son be y.
X+y=60,
X-6=5y,
Y=x-6/5.
Sub y in above eq.
X+x-6/5=60.
5x+x-6=300.
6x=294.
X=49 father age.
Sub x in above.
49+y=60.
Y=11.
After 6 years 11+6=17 years.
Shabana said:
1 decade ago
We can also solve as..
x = son age
y = father's age
x+y=60 -----(1)
(y-6)=5(x-6)-----(2)
by solving (1)&(2) we get x=14 ,y=46
after 6 yrs son age = x+6
= 14+6=20
x = son age
y = father's age
x+y=60 -----(1)
(y-6)=5(x-6)-----(2)
by solving (1)&(2) we get x=14 ,y=46
after 6 yrs son age = x+6
= 14+6=20
Dhanesh P G said:
6 years ago
My solution is given by,
The present sum of ages 60.
So 6 years ago the sum is 48.
Then the ratio is 5:1 it means 5x+x=6x=48.
Then x=8 and,
Age after 6 years is 40+12=52 and 8+12= 20.
The present sum of ages 60.
So 6 years ago the sum is 48.
Then the ratio is 5:1 it means 5x+x=6x=48.
Then x=8 and,
Age after 6 years is 40+12=52 and 8+12= 20.
(1)
Nikhil G said:
5 years ago
x+y = 60 -------------> eqn1
5x-6 = y-6 => 5x = y ----------> eqn2
Equating both equation:
y/5 = 60-y.
y=300-20y.
y=300/19.
y = 14 years.
After 6 years 14+6 = 20.
5x-6 = y-6 => 5x = y ----------> eqn2
Equating both equation:
y/5 = 60-y.
y=300-20y.
y=300/19.
y = 14 years.
After 6 years 14+6 = 20.
(1)
Akshay said:
8 years ago
Simple Steps:
The Sum of Father and Son age: F+S=60.
Before 6 years condition: F-6=5(S-6); F=5S-24,
Put F in F+S=60 i.e,
5S-24+S=60 ; S=14
After Six years, S=14+6 = 20.
The Sum of Father and Son age: F+S=60.
Before 6 years condition: F-6=5(S-6); F=5S-24,
Put F in F+S=60 i.e,
5S-24+S=60 ; S=14
After Six years, S=14+6 = 20.
Rituparna Pati said:
4 years ago
@Amit.
You have already added 6 to the years to convey the present years of both of them. Then why have you added another 6 years. I can't understand! Please explain it.
You have already added 6 to the years to convey the present years of both of them. Then why have you added another 6 years. I can't understand! Please explain it.
(6)
Hiwote end said:
4 years ago
f+s = 60.
f-6 = 5(s-6),
f = 5s-30 +6,
f = 5s-24,
f+s = 60,
5s-24+s = 60,
6s=60+24 = 84,
s = 14 but our target to find son age after 6 years. 14+6= 20.
f-6 = 5(s-6),
f = 5s-30 +6,
f = 5s-24,
f+s = 60,
5s-24+s = 60,
6s=60+24 = 84,
s = 14 but our target to find son age after 6 years. 14+6= 20.
(45)
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