Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 15)
15.
The age of father 10 years ago was thrice the age of his son. Ten years hence, father's age will be twice that of his son. The ratio of their present ages is:
Answer: Option
Explanation:
Let the ages of father and son 10 years ago be 3x and x years respectively.
Then, (3x + 10) + 10 = 2[(x + 10) + 10]
3x + 20 = 2x + 40
x = 20.
Required ratio = (3x + 10) : (x + 10) = 70 : 30 = 7 : 3.
Discussion:
77 comments Page 6 of 8.
Kamwele said:
10 years ago
The age of the son and the father are in the ratio 3:10. If the father have 52 years, how old is the son?
Paritosh said:
8 years ago
If we assume x=10,y=40,it satisfies the given condition And we get ratio as 5:2
is it correct?
is it correct?
(1)
Gimid-pussi said:
5 years ago
Required ratio = (3x + 10) : (x + 10) = 70 : 30 = 7 : 3.
Anyone explain this step in detail.
Anyone explain this step in detail.
(1)
ANGELINE said:
9 years ago
My age 7 years from now is three times my age 15 years ago. What is my present age?
Narayan said:
1 decade ago
Some time it good to solve question without any quick formula.
Thanks Mickey.
Thanks Mickey.
Arshad said:
10 years ago
Ten years hence means ten years from present age or ten years from past.
Manta said:
1 decade ago
Manish your method is looking very easy. But from where 20 has come?
Archi said:
2 decades ago
For 10 years ago it should be minus 10 give me reason please ?
SHUBHAM said:
7 years ago
Ago means subtract so, X+10-10 this statement may be right.
Javeed said:
1 decade ago
10 years ago means 3x - 10. But how it become 3x + 10?
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