Aptitude - Problems on Ages - Discussion

Discussion Forum : Problems on Ages - General Questions (Q.No. 15)
15.
The age of father 10 years ago was thrice the age of his son. Ten years hence, father's age will be twice that of his son. The ratio of their present ages is:
5 : 2
7 : 3
9 : 2
13 : 4
Answer: Option
Explanation:

Let the ages of father and son 10 years ago be 3x and x years respectively.

Then, (3x + 10) + 10 = 2[(x + 10) + 10]

3x + 20 = 2x + 40

x = 20.

Required ratio = (3x + 10) : (x + 10) = 70 : 30 = 7 : 3.

Discussion:
77 comments Page 5 of 8.

Pammy said:   6 years ago
@Archi simple why they have taken minus means 3x is 10 year ago.
3x+10 present age.
3x+10 +10 means 10 years after present age.
(1)

Shubham said:   1 decade ago
Father's age is twice of his son's age. 8 years ago. He was thrice as old as his son. So what will be d son's age at present.

Paritosh said:   8 years ago
Let Akash age is x+4, Akansha age is x.

from the given relation 4x = 3(x+4)
now x=12,x+4=16
Their combined age is 12+16=28.

Vic said:   1 decade ago
TO SOLVE BOTH THE EQUATIONS
3X+10=2X-10 WHERE X=20
SO PUT THE X VALUE IN PLACES OF X
WILL PRODUCE THE RATIO
70:30 i.e=7:3

Gimmeda Pussi said:   5 years ago
Required ratio = (3x + 10) : (x + 10) = 70 : 30 = 7 : 3.

How are we supposed to arrive at this step? Please explain me.
(2)

Priya said:   1 decade ago
How you got the value as x=20 while solving this 2 equ x=30 is coming how if possible please solve that 2 equ please.

Vani said:   10 years ago
@Arshad.

We can calculate from present age either hence or later and also ago, before, after in any age problems.

Mannai shakthi said:   7 years ago
Please give detailed answer and explanation about this sum. How will add the ages when it is mentioned as ago?

Sri said:   1 decade ago
If we take x-10=3(y-10) and x+10=2(y+10) or 3(x-10)=y-10 and 2(x+10)=y+10 also we are getting ratio as 7:3

Sri said:   1 decade ago
Hi sheikh,

In the problem,10 yrs ago father was thrice his son means
x-10=3(y-10) but how 3(x-10)=y-10 ?


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