Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 15)
15.
The age of father 10 years ago was thrice the age of his son. Ten years hence, father's age will be twice that of his son. The ratio of their present ages is:
Answer: Option
Explanation:
Let the ages of father and son 10 years ago be 3x and x years respectively.
Then, (3x + 10) + 10 = 2[(x + 10) + 10]
3x + 20 = 2x + 40
x = 20.
Required ratio = (3x + 10) : (x + 10) = 70 : 30 = 7 : 3.
Discussion:
77 comments Page 4 of 8.
Ramu said:
1 decade ago
Father's age is three years more than three times the son's age.After three years, father's age will be ten years more than twice the son's age. What is the father's present age.
Shiva said:
9 years ago
What is the meaning of fathers age will be twice that of his son?
2(3x + 10 + 10) = (x + 10 + 10).
Why are you taking?
(3x + 10 + 10) = 2((x + 10) + 10).
Please tell me.
2(3x + 10 + 10) = (x + 10 + 10).
Why are you taking?
(3x + 10 + 10) = 2((x + 10) + 10).
Please tell me.
(1)
Rohit said:
1 decade ago
(3x + 10) + 10 = 2[ (x + 10) + 10]. Why we multiply right hand side of eq by 2 instead of left. As father age is twice so why we multiply son's age eq. Please explain?
G Naresh said:
1 decade ago
Let the ages of father and son 10 years ago be 3x and x years respectively.
Then, (3x + 10) + 10 = 2[ (x + 10) + 10].
How it is possible for adding 10 two times?
Then, (3x + 10) + 10 = 2[ (x + 10) + 10].
How it is possible for adding 10 two times?
Anju said:
1 decade ago
@Javeed:
The age is calculating with respect to the present age. So ten years ago means 3x-10. So the present age will b 3x+10.
Now after ten years 3x+10+10.
The age is calculating with respect to the present age. So ten years ago means 3x-10. So the present age will b 3x+10.
Now after ten years 3x+10+10.
Lakshmi said:
1 decade ago
What is the meaning of fathers age will be twice that of his son.
2(3x+10+10) = (x+10+10).
Why are you taking?
(3x+10+10) = 2((x+10)+10).
Please tell me.
2(3x+10+10) = (x+10+10).
Why are you taking?
(3x+10+10) = 2((x+10)+10).
Please tell me.
Lavanya said:
9 years ago
If father's present age is x and how we have to treat x + 3 or 3x in the question?
They mention like son age is 3 times than father age in 3 years hence.
They mention like son age is 3 times than father age in 3 years hence.
Akshat said:
2 years ago
Father's age ten years ago: (3x + 10),
Ten years hence: (2x + 10),
Let son be x years:
(x+10) = (2x + 10),
x = 20.
3x+10 : x+10 = 70 : 30 = 7 : 3.
Ten years hence: (2x + 10),
Let son be x years:
(x+10) = (2x + 10),
x = 20.
3x+10 : x+10 = 70 : 30 = 7 : 3.
(4)
Ankit said:
9 years ago
5 years ago, the sum of ages of father and his son was 30 years. 3 years hence the sum of their ages would be?
Can anyone answer it?
Can anyone answer it?
Ravi Teja said:
2 years ago
I think the answer is incorrect because the year is in ago so, we would subtract the 3x-10 but there is 3x+10.
How it is possible?
How it is possible?
(51)
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