Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 15)
15.
The age of father 10 years ago was thrice the age of his son. Ten years hence, father's age will be twice that of his son. The ratio of their present ages is:
Answer: Option
Explanation:
Let the ages of father and son 10 years ago be 3x and x years respectively.
Then, (3x + 10) + 10 = 2[(x + 10) + 10]
3x + 20 = 2x + 40
x = 20.
Required ratio = (3x + 10) : (x + 10) = 70 : 30 = 7 : 3.
Discussion:
77 comments Page 3 of 8.
Priya said:
9 years ago
In all these questions, we simply assuming son's age as x and father 's age as nx (n=number given).
And why in this question alone we are assuming son's age as x and father 's age as y.
Pleas say the difference.
And why in this question alone we are assuming son's age as x and father 's age as y.
Pleas say the difference.
Rohini Priya said:
7 years ago
Here they considered ages 10 years ago 3x and x, these are not present ages.
Since we solve all problems by having present ages we convert them to the present age.
So the present ages will be 3x+10 and x+10.
Since we solve all problems by having present ages we convert them to the present age.
So the present ages will be 3x+10 and x+10.
(1)
Rachana said:
6 years ago
@Shubham.
Actually, it is not right.
Because initially the age of the boy and his dad are 'x' & '3x' respectively.
10yrs ago it was the case.
Presently, their ages are (x+10) & (3x+10) respectively.
Actually, it is not right.
Because initially the age of the boy and his dad are 'x' & '3x' respectively.
10yrs ago it was the case.
Presently, their ages are (x+10) & (3x+10) respectively.
Praveen said:
1 decade ago
Two emps talking each other , emp1 says to emp2 your age is two times more then me , emp2 exactly, emp1 says but 2 years back your experience twice time of my age, then what is present experience of emp2?
Vamsee menda said:
1 decade ago
Let the ages of father and son 10 years ago be 3x and x years respectively.
Then, (3x + 10) + 10 = 2[(x + 10) + 10].
3x + 20 = 2x + 40.
x = 20.
Required ratio = (3x + 10) : (x + 10) = 70 : 30 = 7 : 3.
Then, (3x + 10) + 10 = 2[(x + 10) + 10].
3x + 20 = 2x + 40.
x = 20.
Required ratio = (3x + 10) : (x + 10) = 70 : 30 = 7 : 3.
Bhuban said:
9 years ago
I need an answer to this question and way of solving.
The present age of the father is four times of his son. When will the son be as old as a father now their ages will be 99 find their present ages?
The present age of the father is four times of his son. When will the son be as old as a father now their ages will be 99 find their present ages?
Shayan said:
2 years ago
Let the ages of father and son 10 years ago be 3x and x years respectively.
Then, (3x + 10) + 10 = 2[(x + 10) + 10],
3x + 20 = 2x + 40.
x = 20..
Required ratio = (3x + 10) : (x + 10) = 70 : 30 = 7 : 3.
Then, (3x + 10) + 10 = 2[(x + 10) + 10],
3x + 20 = 2x + 40.
x = 20..
Required ratio = (3x + 10) : (x + 10) = 70 : 30 = 7 : 3.
(3)
Mickey said:
1 decade ago
Present ages be
father = x
son = y
10 years ago,
father = x-10
son = y-10
a/q
(x-10)= 3(y-10)..........1
10 years hence,
father = x+10
son = y+10
a/q
(x+10)= 2(y+10).......2
We get x=70, y=30.
father = x
son = y
10 years ago,
father = x-10
son = y-10
a/q
(x-10)= 3(y-10)..........1
10 years hence,
father = x+10
son = y+10
a/q
(x+10)= 2(y+10).......2
We get x=70, y=30.
Brindha said:
9 years ago
10 years ago,
Father age is = (3x - 10).
Son age = x.
10 years now.
Father age = 3x - 10 + 10 -------> (2).
Son age is 2 (x + 10) = 2x + 20 -------> (1).
1 = 2.
3x - 10 + 10 = 2x + 20.
x = 20.
Father age is = (3x - 10).
Son age = x.
10 years now.
Father age = 3x - 10 + 10 -------> (2).
Son age is 2 (x + 10) = 2x + 20 -------> (1).
1 = 2.
3x - 10 + 10 = 2x + 20.
x = 20.
Mallik said:
1 decade ago
@Bharat
It is simple. Here we are considering for after 10 years but the question is to find ratio of the present age.
So, (3x+10):(x+10) as x=20
Subs in the above equation, You will get 7:3.
It is simple. Here we are considering for after 10 years but the question is to find ratio of the present age.
So, (3x+10):(x+10) as x=20
Subs in the above equation, You will get 7:3.
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