Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 15)
15.
The age of father 10 years ago was thrice the age of his son. Ten years hence, father's age will be twice that of his son. The ratio of their present ages is:
Answer: Option
Explanation:
Let the ages of father and son 10 years ago be 3x and x years respectively.
Then, (3x + 10) + 10 = 2[(x + 10) + 10]
3x + 20 = 2x + 40
x = 20.
Required ratio = (3x + 10) : (x + 10) = 70 : 30 = 7 : 3.
Discussion:
77 comments Page 7 of 8.
Namgay said:
8 years ago
Why to take 10 in order to find the present ratio?
Marpu Sruthi said:
3 months ago
Good session very clear explanations. Thanks all.
Bharath said:
1 decade ago
Can any one tell me how to derive the ratio?
Neha gupta said:
1 decade ago
After 10 years from the present > Ankur.
Yhxyc said:
8 years ago
Thanks everybody for the given explanation.
(1)
Anu said:
1 decade ago
Can anybody tell me how to find the ratio?
Srk said:
1 decade ago
Only 7:3 is viable when plugged in
Mani said:
1 decade ago
Thanks to all. Now I got some idea.
Ankur said:
1 decade ago
Whats meaning of 10 years hence?
Sanjay said:
8 years ago
Thanks for all the solution.
(1)
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