Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 6)
6.
A man is 24 years older than his son. In two years, his age will be twice the age of his son. The present age of his son is:
Answer: Option
Explanation:
Let the son's present age be x years. Then, man's present age = (x + 24) years.
(x + 24) + 2 = 2(x + 2)
x + 26 = 2x + 4
x = 22.
Discussion:
94 comments Page 5 of 10.
Nilesh kumar said:
1 decade ago
It can be also solved by this? please reply me !
Let the son age be x.
After 2 years he will be twice of his son age..
Then..
2x+2=24.
x=11 then x= 11 the son's age and his father age 2x=2*11 = 22.
Let the son age be x.
After 2 years he will be twice of his son age..
Then..
2x+2=24.
x=11 then x= 11 the son's age and his father age 2x=2*11 = 22.
Jjj said:
1 decade ago
Answer is 20 because after getting value of x which is age after 2 years is 22. So from 22-2=20 is age and his father is 24.
Maha said:
1 decade ago
Why we adding x+2 in left side?
Dana said:
1 decade ago
Why can't we do like this:
(2+2x) =24.
2x = 24-2.
2x = 22.
x = 11.
So then twice will be 22.
(2+2x) =24.
2x = 24-2.
2x = 22.
x = 11.
So then twice will be 22.
Dharm said:
1 decade ago
@Maha.
Let the present age of son is x.
And as given in question the present age of father (f=24+x) and after 2 year later.
Father age = 2x.
In calculating the present age of son as given below as after 2 year.
24+x+2 = 2(x+2).
26+x = 2x+4.
So x = 22.
So because of x = present age of son, we have to add 2 year in present age of son and in this way we can calculate the value of x.
I hope you understand.
Let the present age of son is x.
And as given in question the present age of father (f=24+x) and after 2 year later.
Father age = 2x.
In calculating the present age of son as given below as after 2 year.
24+x+2 = 2(x+2).
26+x = 2x+4.
So x = 22.
So because of x = present age of son, we have to add 2 year in present age of son and in this way we can calculate the value of x.
I hope you understand.
V!cky said:
1 decade ago
Son age x,
Father age x+24,
After two year mean you will add 2 in both side.
(x+24+2) = (x+2).
Father age is twice as son age i.e (x+24+2) = 2(x+2).
x+26 = 2x+4.
::22 = x.
Father age x+24,
After two year mean you will add 2 in both side.
(x+24+2) = (x+2).
Father age is twice as son age i.e (x+24+2) = 2(x+2).
x+26 = 2x+4.
::22 = x.
Aayan said:
1 decade ago
Friends how we take 4 at there?
RAAM said:
1 decade ago
Son age x,
Father age x+24,
After two year mean you will add 2 in both side.
(x+24+2) = (x+2).
Father age is twice as son age i.e. (x+24+2) = 2(x+2).
x+26 = 2x+4.
::22 = x.
But in question he asked present age of son so we have to subtract 2 the answer will be 20 right?
Father age x+24,
After two year mean you will add 2 in both side.
(x+24+2) = (x+2).
Father age is twice as son age i.e. (x+24+2) = 2(x+2).
x+26 = 2x+4.
::22 = x.
But in question he asked present age of son so we have to subtract 2 the answer will be 20 right?
Yash said:
1 decade ago
Anyone please answer me,
They have asked present age of son right?
Then it must be (22-2) = 20.
They have asked present age of son right?
Then it must be (22-2) = 20.
Neocoolboy said:
1 decade ago
In this question people solve this problem by taking x as a 2 year back when father (x) is 24 year more then son (y).
x = y+24.
After two years.
x+2 = 2(y+2) -----------equation 1.
Put x value in equation 1.
y+24+2 = 2y+4.
y = 22.
Why value is 2 year previous is 22?
So present age of son is 24.
x = y+24.
After two years.
x+2 = 2(y+2) -----------equation 1.
Put x value in equation 1.
y+24+2 = 2y+4.
y = 22.
Why value is 2 year previous is 22?
So present age of son is 24.
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