Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 6)
6.
A man is 24 years older than his son. In two years, his age will be twice the age of his son. The present age of his son is:
Answer: Option
Explanation:
Let the son's present age be x years. Then, man's present age = (x + 24) years.
(x + 24) + 2 = 2(x + 2)
x + 26 = 2x + 4
x = 22.
Discussion:
94 comments Page 10 of 10.
Ashu said:
4 years ago
Thanks @Mani.
(3)
Alfred said:
4 years ago
It should be 24 not 22.
"In two years, his age will be twice the age of his son"
so, therefore:
2+24+x = 2x.
x= 26.
Back to present = 24.
"In two years, his age will be twice the age of his son"
so, therefore:
2+24+x = 2x.
x= 26.
Back to present = 24.
(6)
Rajesh said:
4 years ago
After two years, father's age = after 2 years son age twice so;
(x+24) + 2 = 2(x+2) came.
(x+24) + 2 = 2(x+2) came.
(8)
Aditya said:
4 years ago
The answer are given is for sons age so add 2 to all the answers are given.
16, 20, 22, 24.
So after two years his father age will be double so.
32, 40, 44, 48.
But the difference is already given that is 24.
If the Father age increases and also the sons age increases so 24 is constant so 24 double is the answer that is 48.
Thank you.
16, 20, 22, 24.
So after two years his father age will be double so.
32, 40, 44, 48.
But the difference is already given that is 24.
If the Father age increases and also the sons age increases so 24 is constant so 24 double is the answer that is 48.
Thank you.
(46)
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