Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 9)
9.
At present, the ratio between the ages of Arun and Deepak is 4 : 3. After 6 years, Arun's age will be 26 years. What is the age of Deepak at present ?
Answer: Option
Explanation:
Let the present ages of Arun and Deepak be 4x years and 3x years respectively. Then,
4x + 6 = 26 
4x = 20
x = 5.
Deepak's age = 3x = 15 years.
Discussion:
37 comments Page 2 of 4.
PRABIR said:
1 decade ago
Very simple friends, if I am wrong please suggest me:
Answer: Arun : Deepak = 4:3 (present).
6 year after = Arun age is 26.
Now let 6 year before Arun age is = 20.
So let us Arun's ratio is 4 = 20.
If Arun ratio is 1 then his age is 20/4 = 5.
Similarly,
Deepak ration is 3 = 5x3 = 15 (answer).
Answer: Arun : Deepak = 4:3 (present).
6 year after = Arun age is 26.
Now let 6 year before Arun age is = 20.
So let us Arun's ratio is 4 = 20.
If Arun ratio is 1 then his age is 20/4 = 5.
Similarly,
Deepak ration is 3 = 5x3 = 15 (answer).
Javid Mir said:
1 decade ago
Hi to all.
Let the present ages of Arun & Deepak be "x" & "y".
Therefore, x/y = 3/4....equation 1.
Now, Six years after arun's age = 26.
i.e x+6 = 26 => x = 20 years.
Arun's present age = 20 years.
Substituting the value of "x" in equation....1 we get,
20/y = 3/4, on rearranging, we get, y = 20*3/4.
y = 15 years.
Let the present ages of Arun & Deepak be "x" & "y".
Therefore, x/y = 3/4....equation 1.
Now, Six years after arun's age = 26.
i.e x+6 = 26 => x = 20 years.
Arun's present age = 20 years.
Substituting the value of "x" in equation....1 we get,
20/y = 3/4, on rearranging, we get, y = 20*3/4.
y = 15 years.
Naren arya said:
1 decade ago
After 6 years the age of Arun = 26.
Present age of Arun is 26-6 = 20.
=> 4/3 = 20/x.
=> x = 20*3/4.
=> x = 15.
Present age of Arun is 26-6 = 20.
=> 4/3 = 20/x.
=> x = 20*3/4.
=> x = 15.
Rashid Malik said:
10 years ago
Hello @Sohpia.
The derived answer is very clear. Just look following.
Arun age : Deepak age = 4:3.
Let age = x years.
Age of Arun = 4x years.
Age of Deepak = 3x years.
After 6 year Arun age = 4x years + 6 years = 26.
==> x = 5.
Hence age of Arun = 4x = 4*5 = 20 years.
Age of Deepak = 3x = 3*5 = 15 years.
The derived answer is very clear. Just look following.
Arun age : Deepak age = 4:3.
Let age = x years.
Age of Arun = 4x years.
Age of Deepak = 3x years.
After 6 year Arun age = 4x years + 6 years = 26.
==> x = 5.
Hence age of Arun = 4x = 4*5 = 20 years.
Age of Deepak = 3x = 3*5 = 15 years.
Divya said:
9 years ago
Arun age : 4x
Deepak age : 3x.
Then, after 6 yrs Arun age will be 26 : 4x + 6 = 26.
Then, 4x = 20.
x = 5.
Since we need to find Deepak age : 3x = 3 * 5 =15.
Deepak age : 3x.
Then, after 6 yrs Arun age will be 26 : 4x + 6 = 26.
Then, 4x = 20.
x = 5.
Since we need to find Deepak age : 3x = 3 * 5 =15.
Shiloh said:
9 years ago
Please give me the correct explanation for understanding the calculation of the answer.
Shiloh said:
9 years ago
Thank you for all the given explanation.
Atish said:
6 years ago
Consider son's age as 'x' and father's as 'y' so,
x + y = 60.
Then six years ago,
y-6 = 5(x-6).
y-6 = 5x-30.
y = 5x-24.
x+5x-24 = 60.
6x = 84.
x = 84/6 = 14.
So after 6 years 14 + 6 = 20 years old.
x + y = 60.
Then six years ago,
y-6 = 5(x-6).
y-6 = 5x-30.
y = 5x-24.
x+5x-24 = 60.
6x = 84.
x = 84/6 = 14.
So after 6 years 14 + 6 = 20 years old.
Varad kulkarni said:
5 months ago
Let Arun = A
Let Deepak = D
A/D = 3/4
4A - 3D = 0 ---------> (i)
After 6 years, Deepak.
D + 6 = 26.
thus D = 20.
Put this value of D in equation i.
thus , 4A = 60
Thus A = 15 years.
Let Deepak = D
A/D = 3/4
4A - 3D = 0 ---------> (i)
After 6 years, Deepak.
D + 6 = 26.
thus D = 20.
Put this value of D in equation i.
thus , 4A = 60
Thus A = 15 years.
Kiruthika said:
1 decade ago
Thank you shree. You have cleared my doubt.
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