Aptitude - Problems on Ages - Discussion

Let's consider Arun age = X;

And Deepak age = Y;

And the ratio of Arun and Deepak age = 4:3.

So, we have to take X/Y = 4/3;------------> equation 1.

Then, After 6 years, Arun age is 26;

So let's consider X+6 = 26 ==> X = 26-6 ==> X = 20------------->equation 2.

To solve on equation 1 =====> X/Y = 4/3 ==> 3X = 4Y.

Therefore 3X-4Y = 0------------>equation 3.

Let we know the x value of 20.

So we have to apply in equation 3.

= 3(20)-4Y = 0;
= 60-4Y = 0.
= -4Y = -60.

Y = 60/4.
Y = 15;

Deepak (Y) age is 15 years;

There given that the present age of arun and Deepak are 4:3.

So first of all consider the aruns age as 4x and Deepak age is 3x.

And next there is given after 6 means then aruns age after 6 years means 4x+6.

And there is alredy given aruns age is 26 compare both ages i.e. 4x+6=26->4x=20->x=5.

Here we get x=5 then consider present age of Deepak age is 3x so substitute x value there the we get his age is 15 so answer is 15.

Hi friends...Here is a simple method to solve this problem...

Let arun age be x and deepak age be y

The ratio of ages are x/y = 4/3...

from the above equation we can write.

x=4y/3......(1)

given that after 6 years arun age will be 26 years..

x+6 = 26....


4y/3 + 6 = 26.
4y/3 = 20.
4y = 60.
y = 15.

Hence,deepak age is 15 years..
susbstitute the x value from eq (1).

Hi to all.

Let the present ages of Arun & Deepak be "x" & "y".

Therefore, x/y = 3/4....equation 1.

Now, Six years after arun's age = 26.

i.e x+6 = 26 => x = 20 years.

Arun's present age = 20 years.

Substituting the value of "x" in equation....1 we get,

20/y = 3/4, on rearranging, we get, y = 20*3/4.

y = 15 years.

Hello @Sohpia.

The derived answer is very clear. Just look following.

Arun age : Deepak age = 4:3.

Let age = x years.

Age of Arun = 4x years.

Age of Deepak = 3x years.

After 6 year Arun age = 4x years + 6 years = 26.

==> x = 5.

Hence age of Arun = 4x = 4*5 = 20 years.

Age of Deepak = 3x = 3*5 = 15 years.

Very simple friends, if I am wrong please suggest me:

Answer: Arun : Deepak = 4:3 (present).

6 year after = Arun age is 26.

Now let 6 year before Arun age is = 20.

So let us Arun's ratio is 4 = 20.

If Arun ratio is 1 then his age is 20/4 = 5.

Similarly,

Deepak ration is 3 = 5x3 = 15 (answer).

Really simple and clear logic behind it !

Read problem carefully,

2nd statement is very imp.
as per 2nd statement arun's current age is=(26-6)=20 yrs
now 1st statement ,
ratio of age 4:3
4 is for arun age
therefore 20/4=5
now deepak current age as per ratio 5*3=15 year

Have nice day!

Arun age 4x+6=26----------->1
4 is ratio x is variable n 26 is his present age
Deepak age y=3x------------>2
Here y is taken for just to equate, x is variable
Now simplify eq 1
4x=26-6 ==> x=5
Sub x value in eq 2
y=3*5 (y is deepak's age)
y=15
That's it:)

Let x is age of arun and y is age of deepak

Since, X/Y =4/3
then 3X =4Y
Finally X = 4/3Y ---> Eqn 1

After 6 years age of arun will be 26,
X + 6 = 26 ----> Eqn 2
Substitute Eqn 1 into Eqn 2.
4/3Y + 6 = 26
4Y + 18/3 =26
4Y + 18 = 78,
4Y = 60.
Therefore Y = 15.

Let y is the present age of deepak
take ratio as 4X/3X
aftr 6 yrs, (4x+6)/(3x+6)=26/y
first consider numerator,
4x+6=26
4x=20
x=5
now consider
3x=y
3(5)=y
y=15 (No need to add 6 bec present age only they have asked)