Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 9)
9.
At present, the ratio between the ages of Arun and Deepak is 4 : 3. After 6 years, Arun's age will be 26 years. What is the age of Deepak at present ?
Answer: Option
Explanation:
Let the present ages of Arun and Deepak be 4x years and 3x years respectively. Then,
4x + 6 = 26 
4x = 20
x = 5.
Deepak's age = 3x = 15 years.
Discussion:
37 comments Page 2 of 4.
Atish said:
6 years ago
Consider son's age as 'x' and father's as 'y' so,
x + y = 60.
Then six years ago,
y-6 = 5(x-6).
y-6 = 5x-30.
y = 5x-24.
x+5x-24 = 60.
6x = 84.
x = 84/6 = 14.
So after 6 years 14 + 6 = 20 years old.
x + y = 60.
Then six years ago,
y-6 = 5(x-6).
y-6 = 5x-30.
y = 5x-24.
x+5x-24 = 60.
6x = 84.
x = 84/6 = 14.
So after 6 years 14 + 6 = 20 years old.
Anke Lakshmi said:
2 years ago
Let Arun's age be =x.
Let Deepak's age be =y.
Given:
x/y = 4/3 ------->equation 1
After 6 years:
x + 6 = 26 ------> equation 2
Solving equations 1 and 2 we get,
20/y = 4/3.
4y = 60.
y = 15.
Let Deepak's age be =y.
Given:
x/y = 4/3 ------->equation 1
After 6 years:
x + 6 = 26 ------> equation 2
Solving equations 1 and 2 we get,
20/y = 4/3.
4y = 60.
y = 15.
(6)
Mitt said:
9 years ago
This is the simple one.
Present ratio of age is 4 : 3.
Then Aruns future age is 26 after 6 year.
Then 26 - 6 = 20.
Now 20 is from 4 * 5 Aruns present age.
Then Deepak's present age is 3 * 5 = 15.
Present ratio of age is 4 : 3.
Then Aruns future age is 26 after 6 year.
Then 26 - 6 = 20.
Now 20 is from 4 * 5 Aruns present age.
Then Deepak's present age is 3 * 5 = 15.
(4)
Varad kulkarni said:
5 months ago
Let Arun = A
Let Deepak = D
A/D = 3/4
4A - 3D = 0 ---------> (i)
After 6 years, Deepak.
D + 6 = 26.
thus D = 20.
Put this value of D in equation i.
thus , 4A = 60
Thus A = 15 years.
Let Deepak = D
A/D = 3/4
4A - 3D = 0 ---------> (i)
After 6 years, Deepak.
D + 6 = 26.
thus D = 20.
Put this value of D in equation i.
thus , 4A = 60
Thus A = 15 years.
Vijay Anand said:
1 decade ago
NEW METHOD:
Arun and Deepak age is in the ratio 4:3.
After 6 years Aruns age is 26. So current age of Arun is 26-6 = 20.
4:3 = 20:Deepak.
4*Deepak = 20*3.
Deepak = 60/4 = 15.
Arun and Deepak age is in the ratio 4:3.
After 6 years Aruns age is 26. So current age of Arun is 26-6 = 20.
4:3 = 20:Deepak.
4*Deepak = 20*3.
Deepak = 60/4 = 15.
Archana Tripathi said:
1 decade ago
Let arun age is x and deepak age is y.
According to question,
x/y= 4/3 -- (1)
x+6=26
x=20.
From(1)
y=(3/4)*x
Put x=20
y=(3/4)*20
y=15
So deepak age is 15 years.
According to question,
x/y= 4/3 -- (1)
x+6=26
x=20.
From(1)
y=(3/4)*x
Put x=20
y=(3/4)*20
y=15
So deepak age is 15 years.
Msp said:
9 years ago
Arun's current age = 20.
Deepak's age = we don't know (x).
Therefore equation can be written with respect to current age as;
4x/3x = 20/x,
X = 60/4,
X = 15 years.
Deepak's age = we don't know (x).
Therefore equation can be written with respect to current age as;
4x/3x = 20/x,
X = 60/4,
X = 15 years.
(1)
Divya said:
9 years ago
Arun age : 4x
Deepak age : 3x.
Then, after 6 yrs Arun age will be 26 : 4x + 6 = 26.
Then, 4x = 20.
x = 5.
Since we need to find Deepak age : 3x = 3 * 5 =15.
Deepak age : 3x.
Then, after 6 yrs Arun age will be 26 : 4x + 6 = 26.
Then, 4x = 20.
x = 5.
Since we need to find Deepak age : 3x = 3 * 5 =15.
Pavi said:
5 years ago
Gud morning.
Arun: Deepak=4:3 [at present]
So,let=4x:3x.
Gn that after 6 years arun age is 26,
So,
4x = 26.
4X = 20.
X = 5.
Deepak age = 3x.
=3 * 5
=15.
Arun: Deepak=4:3 [at present]
So,let=4x:3x.
Gn that after 6 years arun age is 26,
So,
4x = 26.
4X = 20.
X = 5.
Deepak age = 3x.
=3 * 5
=15.
(1)
Aish said:
1 decade ago
Anyone please explain this problem.
Last year pandit was thrice his sister's age. Next year he is only twice her age. After 5 years what is pandit's age.
Last year pandit was thrice his sister's age. Next year he is only twice her age. After 5 years what is pandit's age.
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