Aptitude - Problems on Ages - Discussion

Given that Arun and Deepak age are in the ratio 4x:3x.

Arun age after 6 years is 4x+6=26.

X=5.

3x=15.

Let arun age is x and deepak age is y.
According to question,

x/y= 4/3 -- (1)
x+6=26
x=20.

From(1)

y=(3/4)*x
Put x=20
y=(3/4)*20
y=15

So deepak age is 15 years.

NEW METHOD:

Arun and Deepak age is in the ratio 4:3.

After 6 years Aruns age is 26. So current age of Arun is 26-6 = 20.

4:3 = 20:Deepak.

4*Deepak = 20*3.

Deepak = 60/4 = 15.

Kindly give the difference between ago, before, hence, after, back? Tell me which operation to be use + or -?

ARUN = 4X.
DEEPAK = 3X.
WE HAVE TO FIND DEEPAK'S AGE,

ie.3X = ?.
4X+6 = 26.
4X = 20-6.
4X = 20.
X = 20/5.
X = 5.

SO, 3X = 3*5 = 15.

After 6 years means 15 +6= 21 years?

Let's consider Arun age = X;

And Deepak age = Y;

And the ratio of Arun and Deepak age = 4:3.

So, we have to take X/Y = 4/3;------------> equation 1.

Then, After 6 years, Arun age is 26;

So let's consider X+6 = 26 ==> X = 26-6 ==> X = 20------------->equation 2.

To solve on equation 1 =====> X/Y = 4/3 ==> 3X = 4Y.

Therefore 3X-4Y = 0------------>equation 3.

Let we know the x value of 20.

So we have to apply in equation 3.

= 3(20)-4Y = 0;
= 60-4Y = 0.
= -4Y = -60.

Y = 60/4.
Y = 15;

Deepak (Y) age is 15 years;