Aptitude - Probability - Discussion
Discussion Forum : Probability - General Questions (Q.No. 7)
7.
In a class, there are 15 boys and 10 girls. Three students are selected at random. The probability that 1 girl and 2 boys are selected, is:
Answer: Option
Explanation:
Let S be the sample space and E be the event of selecting 1 girl and 2 boys.
Then, n(S) | = Number ways of selecting 3 students out of 25 | |||
= 25C3 ` | ||||
|
||||
= 2300. |
n(E) | = (10C1 x 15C2) | ||||||
|
|||||||
= 1050. |
![]() |
n(E) | = | 1050 | = | 21 | . |
n(S) | 2300 | 46 |
Discussion:
54 comments Page 1 of 6.
Prabhu said:
1 decade ago
(10C1 x 15C2) why they are multiplying this ?
They should add the value know .. 10 c1 + 15 c2
They should add the value know .. 10 c1 + 15 c2
Priya said:
1 decade ago
@prabhu.
Even I have the same doubt. Can some intellectual person answer this?
Even I have the same doubt. Can some intellectual person answer this?
Gnana said:
1 decade ago
I too have same doubt. Can any one clarify this, soon.
Mahesh babu said:
1 decade ago
Because he asked 10 girls (and) 15 boys.
Sanjana said:
1 decade ago
If they ask for same collections for example (a bag contains 6 white and 4 black balls.two balls are drawn at random.find the probability that they are of same color) here they are askin for same color in this case we have to use "+" i.e, 6c2+4c2
but here in a above problem they have tld us to select 1 girl out of 10 girls and 2 boys out of 15 boys.and here its not of same combination they are askin for both boy and gal.in this case we have to use "*" i.e, 10C1 x 15C2
Note tat: if its same color or combination go for "+"
If its different combination go for "*"
but here in a above problem they have tld us to select 1 girl out of 10 girls and 2 boys out of 15 boys.and here its not of same combination they are askin for both boy and gal.in this case we have to use "*" i.e, 10C1 x 15C2
Note tat: if its same color or combination go for "+"
If its different combination go for "*"
Prabhat said:
1 decade ago
Nice explanation sanjana.
Abhi said:
1 decade ago
I solved this problem as
(10/25)*(15/24)*(14/23)
because 1st select 1 girl from 10 out of total 25 students, then 1 boy from 15 out of remaining 24 then again 1 boy from 14 boys and total remainig 23 students.... i got 7/46 as my ans.....
Can anyone please tell me whats wrong? please..
(10/25)*(15/24)*(14/23)
because 1st select 1 girl from 10 out of total 25 students, then 1 boy from 15 out of remaining 24 then again 1 boy from 14 boys and total remainig 23 students.... i got 7/46 as my ans.....
Can anyone please tell me whats wrong? please..
Kruvy said:
1 decade ago
You got the Point @Abhi .. :-)
However I cannot help you in this. As I have no clue about is this a right method and robust to solve same kind of problem...??!
Help us.
And I Like this site. Appreciate it @IndiaBix.
However I cannot help you in this. As I have no clue about is this a right method and robust to solve same kind of problem...??!
Help us.
And I Like this site. Appreciate it @IndiaBix.
Swetha said:
1 decade ago
Thanks sanjana.
Al Ford said:
1 decade ago
I have a similar problem. Can anyone explain how to answer this: A class contains 7 women and 7 men. Suppose we choose three random students. How many ways can we choose exactly 1 woman?
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers