Aptitude - Probability
Exercise : Probability - General Questions
- Probability - Formulas
- Probability - General Questions
6.
Two dice are thrown simultaneously. What is the probability of getting two numbers whose product is even?
Answer: Option
Explanation:
In a simultaneous throw of two dice, we have n(S) = (6 x 6) = 36.
Then, E | = {(1, 2), (1, 4), (1, 6), (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6), (3, 2), (3, 4), (3, 6), (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6), (5, 2), (5, 4), (5, 6), (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)} |
n(E) = 27.
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n(E) | = | 27 | = | 3 | . |
n(S) | 36 | 4 |
7.
In a class, there are 15 boys and 10 girls. Three students are selected at random. The probability that 1 girl and 2 boys are selected, is:
Answer: Option
Explanation:
Let S be the sample space and E be the event of selecting 1 girl and 2 boys.
Then, n(S) | = Number ways of selecting 3 students out of 25 | |||
= 25C3 ` | ||||
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= 2300. |
n(E) | = (10C1 x 15C2) | ||||||
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= 1050. |
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n(E) | = | 1050 | = | 21 | . |
n(S) | 2300 | 46 |
8.
In a lottery, there are 10 prizes and 25 blanks. A lottery is drawn at random. What is the probability of getting a prize?
Answer: Option
Explanation:
P (getting a prize) = | 10 | = | 10 | = | 2 | . |
(10 + 25) | 35 | 7 |
9.
From a pack of 52 cards, two cards are drawn together at random. What is the probability of both the cards being kings?
Answer: Option
Explanation:
Let S be the sample space.
Then, n(S) = 52C2 = | (52 x 51) | = 1326. |
(2 x 1) |
Let E = event of getting 2 kings out of 4.
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(4 x 3) | = 6. |
(2 x 1) |
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n(E) | = | 6 | = | 1 | . |
n(S) | 1326 | 221 |
10.
Two dice are tossed. The probability that the total score is a prime number is:
Answer: Option
Explanation:
Clearly, n(S) = (6 x 6) = 36.
Let E = Event that the sum is a prime number.
Then E | = { (1, 1), (1, 2), (1, 4), (1, 6), (2, 1), (2, 3), (2, 5), (3, 2), (3, 4), (4, 1), (4, 3), (5, 2), (5, 6), (6, 1), (6, 5) } |
n(E) = 15.
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n(E) | = | 15 | = | 5 | . |
n(S) | 36 | 12 |
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