Aptitude - Probability - Discussion
Discussion Forum : Probability - General Questions (Q.No. 11)
11.
A card is drawn from a pack of 52 cards. The probability of getting a queen of club or a king of heart is:
Answer: Option
Explanation:
Here, n(S) = 52.
Let E = event of getting a queen of club or a king of heart.
Then, n(E) = 2.
 P(E) = |
n(E) | = | 2 | = | 1 | . |
| n(S) | 52 | 26 |
Discussion:
55 comments Page 5 of 6.
Pooja said:
1 decade ago
Prob of 1 random selection n(S) = 52C1 = 52.
Queen of club = (13C1)/13 OR
King of heart = (13C1)/13.
So addition is n(E) = 2.
Finally,
p(E) = n(E)/n(S)
= 2/52 i.e 1/26.
Queen of club = (13C1)/13 OR
King of heart = (13C1)/13.
So addition is n(E) = 2.
Finally,
p(E) = n(E)/n(S)
= 2/52 i.e 1/26.
Madhu said:
1 decade ago
According to me, club And Heart contain 13, 13 cards. Given 1 queen in club or 1 king in heart. So the answer is n(s) =1.
And n(E) = 26. So p(E) =n(E) /n(s) = 1/26.
And n(E) = 26. So p(E) =n(E) /n(s) = 1/26.
KHAN said:
1 decade ago
See actually only one queen is there in club and only one king in heart therefore it will be : 1C1+1C1=2.
2/52=1/26.
2/52=1/26.
Raj said:
1 decade ago
Not satisfied please help
since there are 13 cards of each club and heart category and each contain single king or queen then the answer should be 1/2.
ex:(13C1+13C1)/52C1
please help if wrong
since there are 13 cards of each club and heart category and each contain single king or queen then the answer should be 1/2.
ex:(13C1+13C1)/52C1
please help if wrong
Subrata Acharjee said:
1 decade ago
There are 13 cards in club and 13 also in heart.
so the probability of getting a queen of club is 1/13
and the probability of getting a king of heart is 1/13
so The probability of getting a queen of club or a king of heart is (1/13 + 1/13)
= 2/13
so the probability of getting a queen of club is 1/13
and the probability of getting a king of heart is 1/13
so The probability of getting a queen of club or a king of heart is (1/13 + 1/13)
= 2/13
M0rfeen said:
1 decade ago
@kanan i was thinking same as you 4C1 X 4C1)/52C1
but its only right when they have asked just "queen and king" as there are 4 queen and 4 king but here they have asked "Club queen or Heart King" so there is only one Club queen and one Heart King so it's 1/52+1/52
but its only right when they have asked just "queen and king" as there are 4 queen and 4 king but here they have asked "Club queen or Heart King" so there is only one Club queen and one Heart King so it's 1/52+1/52
Kosakshi Pasapugazh said:
1 decade ago
Answer is 1/52.. B'coz the question is Queen OR King... Not Queen and King....
Garima gupta said:
1 decade ago
@kasi:perfect answer.
Rajesh said:
1 decade ago
The correct answer is-
n(F)=1+1
n(T)=52c1
then,
P=n(E)/n(T)=2/52
=1/26
n(F)=1+1
n(T)=52c1
then,
P=n(E)/n(T)=2/52
=1/26
MOHAMMAD IMRAN said:
1 decade ago
Excellent answer by kasi.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers