Aptitude - Probability - Discussion

Discussion Forum : Probability - General Questions (Q.No. 6)
6.
Two dice are thrown simultaneously. What is the probability of getting two numbers whose product is even?
1
2
3
4
3
8
5
16
Answer: Option
Explanation:

In a simultaneous throw of two dice, we have n(S) = (6 x 6) = 36.

Then, E = {(1, 2), (1, 4), (1, 6), (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6), (3, 2), (3, 4),
     (3, 6), (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6), (5, 2), (5, 4), (5, 6), (6, 1),
     (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)}

n(E) = 27.

P(E) = n(E) = 27 = 3 .
n(S) 36 4

Discussion:
67 comments Page 5 of 7.

Ziku said:   1 decade ago
Product must be a number which might be an even or an odd. So P(even/odd) = 1/2.

BHARATH said:   9 years ago
@Shubhankar & @Sabyasachi.

Thanks for giving an easy method to understand.

Anusuya said:   8 years ago
I don't understand why take product why only take sum?

Please, guys explain.

Priya said:   8 years ago
@Shubhanka.

I can't understand your method. Can you explain it in detail?

Chiru said:   1 decade ago
Still it takes long time know?

I am getting concept but say in short way.

Prateek said:   9 years ago
I have the same question. Just like Keisha. Please, someone give answer.

Swathy said:   9 years ago
Really useful information for non-maths students like me. Thank to all.

Yaswanth said:   1 decade ago
Is there any other questions and shortcuts regarding these problems ?

Chetna Chauhan said:   3 years ago
Yes, It is easy for understanding. Thanks, everyone for explaining.
(1)

Soumya said:   1 decade ago
There is not any either easy solution? Which must not be confusing?


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