Aptitude - Probability - Discussion
Discussion Forum : Probability - General Questions (Q.No. 6)
6.
Two dice are thrown simultaneously. What is the probability of getting two numbers whose product is even?
Answer: Option
Explanation:
In a simultaneous throw of two dice, we have n(S) = (6 x 6) = 36.
| Then, E | = {(1, 2), (1, 4), (1, 6), (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6), (3, 2), (3, 4), (3, 6), (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6), (5, 2), (5, 4), (5, 6), (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)} |
n(E) = 27.
| P(E) = |
n(E) | = | 27 | = | 3 | . |
| n(S) | 36 | 4 |
Discussion:
67 comments Page 4 of 7.
Shishirkumar said:
8 years ago
3 cases.
even* odd=even.
even * even =even.
odd * even= even.
add all
(3/6*3/6)+3/6*3/6)+(3/6*3/6)=3/4.
even* odd=even.
even * even =even.
odd * even= even.
add all
(3/6*3/6)+3/6*3/6)+(3/6*3/6)=3/4.
Phani said:
1 decade ago
Provide shortcuts also with these explanations then we can able to do solve the problems very fastly.
NIKHIL said:
1 decade ago
Sir please any one explain in a question ask product of even number but in solution shown odd number.
Maruthi said:
1 decade ago
Sir i am not getting probability event....three dice means how can we take the events...pls tell me.
Andrew007 said:
9 years ago
Even + odd = odd.
Example: even 2 + odd 3= 5 which is odd.
So, the answer should be 1/2.
Example: even 2 + odd 3= 5 which is odd.
So, the answer should be 1/2.
Thangamuthu said:
1 decade ago
How it is.....? only 18 even numbers combinations are possible ....?so ans must be 1/2. .
Yebs said:
4 years ago
n(s) = 36*2=72.
n(E)=27*2.
Since it's two dice thrown simultaneously.
Then; 54/72 = 3/4.
n(E)=27*2.
Since it's two dice thrown simultaneously.
Then; 54/72 = 3/4.
(3)
Narendra said:
1 decade ago
Hi @bharath. K.
I am not understand below line.
n(S) = 6*6 = 36.
Why we are taking 6*6?
I am not understand below line.
n(S) = 6*6 = 36.
Why we are taking 6*6?
Scalar said:
9 years ago
Shouldn't the answer be 1/2?
The solution lists odd combinations, such as 4 and 1.
The solution lists odd combinations, such as 4 and 1.
Ch. Anusha said:
1 decade ago
I do not understand because it is too lengthy process. Please tell the shortcuts.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers