Aptitude - Probability - Discussion
Discussion Forum : Probability - General Questions (Q.No. 6)
6.
Two dice are thrown simultaneously. What is the probability of getting two numbers whose product is even?
Answer: Option
Explanation:
In a simultaneous throw of two dice, we have n(S) = (6 x 6) = 36.
| Then, E | = {(1, 2), (1, 4), (1, 6), (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6), (3, 2), (3, 4), (3, 6), (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6), (5, 2), (5, 4), (5, 6), (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)} |
n(E) = 27.
| P(E) = |
n(E) | = | 27 | = | 3 | . |
| n(S) | 36 | 4 |
Discussion:
67 comments Page 2 of 7.
Chetna Chauhan said:
3 years ago
Yes, It is easy for understanding. Thanks, everyone for explaining.
(1)
Priya said:
8 years ago
@Shubhanka.
I can't understand your method. Can you explain it in detail?
I can't understand your method. Can you explain it in detail?
Pravin atrekar said:
9 years ago
Wrong answer is mentioned here because we have to find the product not sum who's output comes even so and 9/35 =1/4.
Prateek said:
9 years ago
I have the same question. Just like Keisha. Please, someone give answer.
BHARATH said:
9 years ago
@Shubhankar & @Sabyasachi.
Thanks for giving an easy method to understand.
Thanks for giving an easy method to understand.
Naren said:
9 years ago
It may be also a short method:
Odd no 1st dice 1, 3, 5 = 3. 2nd dice odd no 1, 2, 3 = 3 hence 3 * 3 = 9.
Therefore, the product of even no 1-9/36 = 34.
Odd no 1st dice 1, 3, 5 = 3. 2nd dice odd no 1, 2, 3 = 3 hence 3 * 3 = 9.
Therefore, the product of even no 1-9/36 = 34.
Scalar said:
9 years ago
Shouldn't the answer be 1/2?
The solution lists odd combinations, such as 4 and 1.
The solution lists odd combinations, such as 4 and 1.
Andrew007 said:
9 years ago
Even + odd = odd.
Example: even 2 + odd 3= 5 which is odd.
So, the answer should be 1/2.
Example: even 2 + odd 3= 5 which is odd.
So, the answer should be 1/2.
Hrishi said:
9 years ago
@Chetana.
You explained the solution in a simple way. Great.
You explained the solution in a simple way. Great.
Ashraf said:
9 years ago
Even = odd * even + even * even.
Odd = odd * odd oly
So in a dice odd = 1 3 5.
Another dice odd 135.
135
135 matrix e combination 9.
Odd possibility = 9/36.
Even possibility = 27/36.
Odd = odd * odd oly
So in a dice odd = 1 3 5.
Another dice odd 135.
135
135 matrix e combination 9.
Odd possibility = 9/36.
Even possibility = 27/36.
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