Aptitude - Probability - Discussion

Discussion Forum : Probability - General Questions (Q.No. 6)
6.
Two dice are thrown simultaneously. What is the probability of getting two numbers whose product is even?
1
2
3
4
3
8
5
16
Answer: Option
Explanation:

In a simultaneous throw of two dice, we have n(S) = (6 x 6) = 36.

Then, E = {(1, 2), (1, 4), (1, 6), (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6), (3, 2), (3, 4),
     (3, 6), (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6), (5, 2), (5, 4), (5, 6), (6, 1),
     (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)}

n(E) = 27.

P(E) = n(E) = 27 = 3 .
n(S) 36 4

Discussion:
67 comments Page 7 of 7.

Soumya said:   1 decade ago
There is not any either easy solution? Which must not be confusing?

NIKHIL said:   1 decade ago
Sir please any one explain in a question ask product of even number but in solution shown odd number.

Ziku said:   1 decade ago
Product must be a number which might be an even or an odd. So P(even/odd) = 1/2.

Shubhankar said:   10 years ago
Simply do.

1 = 3 times even nos (ex-1*2=2, 1*4=4, 1*6=6).
2 = 6 times.
3 = 3 times.
4 = 6 times (4*1=4, 4*2=8. Etc).
5 = 3 times even nos.
6 = 6 times.

Total times even numbers = 27; n(s) = 6*6 = 36.

Now by formula p(e) = N(E)/N(S).

27/36 = 3/4.

Sabyasachi said:   10 years ago
Just keep in the mind that odd is (e.g: 1, 3, 6) multiply with the even number i.e. 3 times each to make even.

And the even number is multiply with the all numbers (1, 2.6).

Solution:

1, 3, 5 (3 times each) i.e -3*3 = 9 times.

2, 4, 6 (6 times each) i.e -3*6 = 18 times.

So total favorable event-18+9 = 27.

Total no of event = 36.

So answer is = 27/36 = 3/4.

Tarunaa said:   9 years ago
I am unable to understand.

Please someone explain in briefly!

Adi said:   9 years ago
Question is what are the chances of getting two numbers whose product (multiplication) is even number (2, 4, 6).


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