Aptitude - Probability - Discussion
Discussion Forum : Probability - General Questions (Q.No. 4)
4.
What is the probability of getting a sum 9 from two throws of a dice?
Answer: Option
Explanation:
In two throws of a dice, n(S) = (6 x 6) = 36.
Let E = event of getting a sum ={(3, 6), (4, 5), (5, 4), (6, 3)}.
 P(E) = |
n(E) | = | 4 | = | 1 | . |
| n(S) | 36 | 9 |
Discussion:
52 comments Page 5 of 6.
Saravana said:
2 years ago
(1/8) is also possible for the answer. Right?
(3)
Ankita said:
1 decade ago
How do we know that we have to pick up 6 * 6?
Srinivas said:
1 decade ago
n(s)=36
n(a)=[36][45][63][54]
p(a)=4/36=1/9
n(a)=[36][45][63][54]
p(a)=4/36=1/9
John said:
1 decade ago
Do you need to do all thus working out?
Shankar said:
9 years ago
Thanks for your solution @Sreejith.
Anurag said:
1 decade ago
Ankita:.
Because 6c1 * 6c1 is 36.
Because 6c1 * 6c1 is 36.
Krish said:
1 decade ago
How it could be n(s)= (6 x 6)
Umar said:
9 years ago
9 + 9 = 18,
=> 2/18 = 1/9.
=> 2/18 = 1/9.
Malasrvizhi said:
1 decade ago
How did get the sum element?
Rama said:
1 decade ago
How to select n(e) = 4.
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