Aptitude - Pipes and Cistern - Discussion

Discussion Forum : Pipes and Cistern - General Questions (Q.No. 15)
15.
Three pipes A, B and C can fill a tank in 6 hours. After working at it together for 2 hours, C is closed and A and B can fill the remaining part in 7 hours. The number of hours taken by C alone to fill the tank is:
10
12
14
16
Answer: Option
Explanation:

Part filled in 2 hours = 2 = 1
6 3

Remaining part = 1 - 1 = 2 .
3 3

(A + B)'s 7 hour's work = 2
3

(A + B)'s 1 hour's work = 2
21

C's 1 hour's work = { (A + B + C)'s 1 hour's work } - { (A + B)'s 1 hour's work }

   = 1 - 2 = 1
6 21 14

C alone can fill the tank in 14 hours.

Discussion:
44 comments Page 4 of 5.

Deepa said:   8 years ago
1/A+1/B+1/C=1/6,
1/A+1/B=1/7.
1/6-1/7=1/42,
42/3=14.

Rahul Namdev said:   9 years ago
LCM of 1/6 . 1/2 . 1/7 = 84.
So, 6/84 = 14.

Dipali Toraskar said:   4 years ago
Can you explain about the Remaining part?
(1)

Tamaghna said:   1 decade ago
What's the 1 hour calculation of (a+b+c)?

Jigme Wangchuk said:   5 years ago
How 1/6 - 2/21 = 1 /14? Explain please.

Vickneswari said:   7 years ago
Why did you divide 42 by 3?

And how?

Pooja said:   10 years ago
1/6-2/21 = 1/14 explain me in detail.

Arun said:   1 decade ago
Can't understand explain it clearly.

Sachin said:   6 years ago
Not getting this, please explain it.

Vishaka said:   1 decade ago
How to calculate (A+B) in 7 hours ?


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