Aptitude - Pipes and Cistern - Discussion
Discussion Forum : Pipes and Cistern - General Questions (Q.No. 15)
15.
Three pipes A, B and C can fill a tank in 6 hours. After working at it together for 2 hours, C is closed and A and B can fill the remaining part in 7 hours. The number of hours taken by C alone to fill the tank is:
Answer: Option
Explanation:
Part filled in 2 hours = | 2 | = | 1 |
6 | 3 |
Remaining part = | ![]() |
1 - | 1 | ![]() |
= | 2 | . |
3 | 3 |
![]() |
2 |
3 |
(A + B)'s 1 hour's work = | 2 |
21 |
C's 1 hour's work = { (A + B + C)'s 1 hour's work } - { (A + B)'s 1 hour's work }
= | ![]() |
1 | - | 2 | ![]() |
= | 1 |
6 | 21 | 14 |
C alone can fill the tank in 14 hours.
Discussion:
44 comments Page 4 of 5.
Deepa said:
8 years ago
1/A+1/B+1/C=1/6,
1/A+1/B=1/7.
1/6-1/7=1/42,
42/3=14.
1/A+1/B=1/7.
1/6-1/7=1/42,
42/3=14.
Rahul Namdev said:
9 years ago
LCM of 1/6 . 1/2 . 1/7 = 84.
So, 6/84 = 14.
So, 6/84 = 14.
Dipali Toraskar said:
4 years ago
Can you explain about the Remaining part?
(1)
Tamaghna said:
1 decade ago
What's the 1 hour calculation of (a+b+c)?
Jigme Wangchuk said:
5 years ago
How 1/6 - 2/21 = 1 /14? Explain please.
Vickneswari said:
7 years ago
Why did you divide 42 by 3?
And how?
And how?
Pooja said:
10 years ago
1/6-2/21 = 1/14 explain me in detail.
Arun said:
1 decade ago
Can't understand explain it clearly.
Sachin said:
6 years ago
Not getting this, please explain it.
Vishaka said:
1 decade ago
How to calculate (A+B) in 7 hours ?
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