Aptitude - Pipes and Cistern - Discussion

Discussion Forum : Pipes and Cistern - General Questions (Q.No. 4)
4.
Two pipes A and B can fill a cistern in 37 minutes and 45 minutes respectively. Both pipes are opened. The cistern will be filled in just half an hour, if the B is turned off after:
5 min.
9 min.
10 min.
15 min.
Answer: Option
Explanation:

Let B be turned off after x minutes. Then,

Part filled by (A + B) in x min. + Part filled by A in (30 -x) min. = 1.

x 2 + 1 + (30 - x). 2 = 1
75 45 75

11x + (60 -2x) = 1
225 75

11x + 180 - 6x = 225.

x = 9.

Discussion:
90 comments Page 3 of 9.

Kunal Aryan said:   9 years ago
For this type of question use Short Trick :

[Y*(1 - t / x)]
Here X= 75/2 ; Y=45 and t= 30mint. (ie. half an hour).
Soln: 45*(1 - 30 * 2 / 75) = 9 mints. answer.

Madhubala said:   8 years ago
For 1min it takes( 2/75).
For 30 min (1/2 hour) it takes 2/75*30=4/5 part.
So remaining only 1 part out of 5 which is going to fill by B.
So (1/5*45) = 9 min.

Sandhiya said:   8 years ago
Can anyone explain how 2/75 comes? please.

Manikant said:   8 years ago
2/75 + 1/45 = 8/225.

How it can be 11/225?

Satendra singh said:   9 years ago
(30-X) how came? Please explain me.

Sudhakar p said:   9 years ago
I can't understand please explain clearly.

Kumar said:   9 years ago
@Arshad1605, Please tell me how 9 came after 105/11?

Tapz patel said:   8 years ago
A*(A'work)+B*(B'work)=1,
It means 30(A)+x(B)=1,
Then, x=9.

Deepak said:   8 years ago
Best solution:

Parts filled by A in 1 min = 2/75
Parts filled by B in 1 min = 1/45
Now;
In 30 min tank is full so,
Parts filled by A in 30 min = 30*2/75 =60/75
Parts filled by B in X min = X/45
So, 60/75 + X/45 = 1
Therefore ,X = 9 min.

Khagendra said:   8 years ago
@Kasi Srinivas.

Nice explanation, anyone can easily understand this, Thanks.


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