Aptitude - Pipes and Cistern - Discussion
Discussion Forum : Pipes and Cistern - General Questions (Q.No. 14)
14.
Three taps A, B and C can fill a tank in 12, 15 and 20 hours respectively. If A is open all the time and B and C are open for one hour each alternately, the tank will be full in:
Answer: Option
Explanation:
| (A + B)'s 1 hour's work = |  |
1 | + | 1 |  |
= | 9 | = | 3 | . |
| 12 | 15 | 60 | 20 |
| (A + C)'s hour's work = | |
1 | + | 1 | |
= | 8 | = | 2 | . |
| 12 | 20 | 60 | 15 |
| Part filled in 2 hrs = | |
3 | + | 2 | |
= | 17 | . |
| 20 | 15 | 60 |
| Part filled in 6 hrs = | |
3 x | 17 | |
= | 17 | . |
| 60 | 20 |
| Remaining part = | |
1 - | 17 | |
= | 3 | . |
| 20 | 20 |
| Now, it is the turn of A and B and | 3 | part is filled by A and B in 1 hour. |
| 20 |
Total time taken to fill the tank = (6 + 1) hrs = 7 hrs.
Discussion:
52 comments Page 6 of 6.
Narendra said:
10 years ago
Let's assume B works for x hours and C for y hours. So A will be working for x+y hours.
= (x+y)/12 + x/15 + y/20 = 1 (tank having 1 part).
= 9x + 8y = 60.
x = 4; y = 3.
= (x+y)/12 + x/15 + y/20 = 1 (tank having 1 part).
= 9x + 8y = 60.
x = 4; y = 3.
Brajesh said:
9 years ago
It was a nice solution @Alvin .
Thank you.
Thank you.
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