Aptitude - Pipes and Cistern - Discussion
Discussion Forum : Pipes and Cistern - General Questions (Q.No. 14)
14.
Three taps A, B and C can fill a tank in 12, 15 and 20 hours respectively. If A is open all the time and B and C are open for one hour each alternately, the tank will be full in:
Answer: Option
Explanation:
(A + B)'s 1 hour's work = | ![]() |
1 | + | 1 | ![]() |
= | 9 | = | 3 | . |
12 | 15 | 60 | 20 |
(A + C)'s hour's work = | ![]() |
1 | + | 1 | ![]() |
= | 8 | = | 2 | . |
12 | 20 | 60 | 15 |
Part filled in 2 hrs = | ![]() |
3 | + | 2 | ![]() |
= | 17 | . |
20 | 15 | 60 |
Part filled in 6 hrs = | ![]() |
3 x | 17 | ![]() |
= | 17 | . |
60 | 20 |
Remaining part = | ![]() |
1 - | 17 | ![]() |
= | 3 | . |
20 | 20 |
Now, it is the turn of A and B and | 3 | part is filled by A and B in 1 hour. |
20 |
Total time taken to fill the tank = (6 + 1) hrs = 7 hrs.
Discussion:
52 comments Page 5 of 6.
Anu sharma said:
1 decade ago
i did not understand method plz help
Sanjay said:
1 decade ago
Its very simple.
Part filled in 1st and 2nd hour:
1/12+1/15+1/12+1/20 = 17/60.
Part filled : Time taken
17/60 : 2 hr
1 : ?
By solving this we will get 6.8 that is nearby 7.
Part filled in 1st and 2nd hour:
1/12+1/15+1/12+1/20 = 17/60.
Part filled : Time taken
17/60 : 2 hr
1 : ?
By solving this we will get 6.8 that is nearby 7.
ALVIN said:
1 decade ago
Please carefully read the question A is open for all times, B and C are opened alternatively for one hour, that means if B is opened for 1st hour that time C is closed(A and B filling the tank) For 2nd hour B is closed C is opened(A and C is Filling the tank)3rd hour B opened C closed and so on...
1st hour:
1 hour work of A and B is 1/12+1/15 = 3/20.
2nd hour:
1 hour work of A and C is 1/12+1/20 = 2/15.
3rd hour:
1 hour work of A and B is 1/12+1/15 = 3/20.
4th hour:
1 hour work of A and C is 1/12+1/20 = 2/15.
5th hour:
1 hour work of A and B is 1/12+1/15 = 3/20.
6th hour:
1 hour work of A and C is 1/12+1/20 = 2/15.
7th hour:
1 hour work of A and B is 1/12+1/15 = 3/20.
(Until you have to calculate 60/60).
If we add the whole we will get 1 is the answer that is capacity of tank.
3/20+2/15+3/20+2/15+3/20+2/15+3/20+2/15+3/20 = (9+8+9+8+9+8+9)/60 = 1.
Hence, time taken to fill the tank is 7 hours.
1st hour:
1 hour work of A and B is 1/12+1/15 = 3/20.
2nd hour:
1 hour work of A and C is 1/12+1/20 = 2/15.
3rd hour:
1 hour work of A and B is 1/12+1/15 = 3/20.
4th hour:
1 hour work of A and C is 1/12+1/20 = 2/15.
5th hour:
1 hour work of A and B is 1/12+1/15 = 3/20.
6th hour:
1 hour work of A and C is 1/12+1/20 = 2/15.
7th hour:
1 hour work of A and B is 1/12+1/15 = 3/20.
(Until you have to calculate 60/60).
If we add the whole we will get 1 is the answer that is capacity of tank.
3/20+2/15+3/20+2/15+3/20+2/15+3/20+2/15+3/20 = (9+8+9+8+9+8+9)/60 = 1.
Hence, time taken to fill the tank is 7 hours.
Kasinath @Hyd said:
1 decade ago
(A + B)'s 1 hour's work= 1/12+1/15 = 3/20.
(A + C)'s 1 hour's work =1/12+1/20 = 2/15.
Therefore (3/20 + 2/15)= 17/60 part of work is completed in first 2 hrs.
17/60 part of work completed in ------- 2hrs.
1 part (full work) completed in ------- x hrs.
Now cross multiply => x= 2(60/17) = 7hrs.
(A + C)'s 1 hour's work =1/12+1/20 = 2/15.
Therefore (3/20 + 2/15)= 17/60 part of work is completed in first 2 hrs.
17/60 part of work completed in ------- 2hrs.
1 part (full work) completed in ------- x hrs.
Now cross multiply => x= 2(60/17) = 7hrs.
Paridhi said:
1 decade ago
It written part filled in six hours then why is it multiplied by 3 and not six?
Vino said:
1 decade ago
Take LCM a, b, c = 180, tank capacity 180 liters.
a - 15 liter per hrs.
b - 12.
c - 9.
1hrs a+b = 27 liter.
1hrs a+c = 24 liter.
In choice more than 6 hrs.
= 27*4 = 108.
= 24*3 = 72.
Total 180 liters in 7 hrs.
a - 15 liter per hrs.
b - 12.
c - 9.
1hrs a+b = 27 liter.
1hrs a+c = 24 liter.
In choice more than 6 hrs.
= 27*4 = 108.
= 24*3 = 72.
Total 180 liters in 7 hrs.
Gnanamayil.k said:
1 decade ago
I feel its all lengthy calculation. Is there any simple shortcut method?
Potato singh said:
1 decade ago
Yes, take a bucket of 60 ltr capacity. Install 3 taps in your bathroom and get started.
Arun said:
1 decade ago
1 hr tank can fill 3/20 -> (1/12+1/15).
2nd hr tank can fill 3/20+2/15 = 17/60.
For 2 hr it fills 17/60 then for 1 hr it fills 17/120 -> (1/2*17/60).
Consider 17 table 17*6 = 102, so in six hours it it fills 102/120 and next hr B Pipe will be open and.
Fills as 102/120+3/20 = 1. So 7 hrs it will take.
Another way:
For 2 hrs it fills 17/60.
Consider next 2 hrs i.e. 4 hrs 2*17/60 = 34/60.
Consider next 2 hrs i.e 6 hrs 51/60 only 9 is less for 60 i.e to full.
So next 1 hr b pipe open 51/60+9/60 = 1.
2nd hr tank can fill 3/20+2/15 = 17/60.
For 2 hr it fills 17/60 then for 1 hr it fills 17/120 -> (1/2*17/60).
Consider 17 table 17*6 = 102, so in six hours it it fills 102/120 and next hr B Pipe will be open and.
Fills as 102/120+3/20 = 1. So 7 hrs it will take.
Another way:
For 2 hrs it fills 17/60.
Consider next 2 hrs i.e. 4 hrs 2*17/60 = 34/60.
Consider next 2 hrs i.e 6 hrs 51/60 only 9 is less for 60 i.e to full.
So next 1 hr b pipe open 51/60+9/60 = 1.
Swetha said:
10 years ago
Please say short cut method for problem 14 it is length process.
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