Aptitude - Pipes and Cistern - Discussion

Discussion Forum : Pipes and Cistern - General Questions (Q.No. 14)
14.
Three taps A, B and C can fill a tank in 12, 15 and 20 hours respectively. If A is open all the time and B and C are open for one hour each alternately, the tank will be full in:
6 hours
6 2 hours
3
7 hours
7 1 hours
2
Answer: Option
Explanation:

(A + B)'s 1 hour's work = 1 + 1 = 9 = 3 .
12 15 60 20

(A + C)'s hour's work = 1 + 1 = 8 = 2 .
12 20 60 15

Part filled in 2 hrs = 3 + 2 = 17 .
20 15 60

Part filled in 6 hrs = 3 x 17 = 17 .
60 20

Remaining part = 1 - 17 = 3 .
20 20

Now, it is the turn of A and B and 3 part is filled by A and B in 1 hour.
20

Total time taken to fill the tank = (6 + 1) hrs = 7 hrs.

Discussion:
52 comments Page 5 of 6.

Anu sharma said:   1 decade ago
i did not understand method plz help

Sanjay said:   1 decade ago
Its very simple.

Part filled in 1st and 2nd hour:

1/12+1/15+1/12+1/20 = 17/60.

Part filled : Time taken
17/60 : 2 hr
1 : ?

By solving this we will get 6.8 that is nearby 7.

ALVIN said:   1 decade ago
Please carefully read the question A is open for all times, B and C are opened alternatively for one hour, that means if B is opened for 1st hour that time C is closed(A and B filling the tank) For 2nd hour B is closed C is opened(A and C is Filling the tank)3rd hour B opened C closed and so on...

1st hour:

1 hour work of A and B is 1/12+1/15 = 3/20.

2nd hour:

1 hour work of A and C is 1/12+1/20 = 2/15.

3rd hour:

1 hour work of A and B is 1/12+1/15 = 3/20.

4th hour:

1 hour work of A and C is 1/12+1/20 = 2/15.

5th hour:

1 hour work of A and B is 1/12+1/15 = 3/20.

6th hour:

1 hour work of A and C is 1/12+1/20 = 2/15.

7th hour:

1 hour work of A and B is 1/12+1/15 = 3/20.

(Until you have to calculate 60/60).

If we add the whole we will get 1 is the answer that is capacity of tank.

3/20+2/15+3/20+2/15+3/20+2/15+3/20+2/15+3/20 = (9+8+9+8+9+8+9)/60 = 1.

Hence, time taken to fill the tank is 7 hours.

Kasinath @Hyd said:   1 decade ago
(A + B)'s 1 hour's work= 1/12+1/15 = 3/20.

(A + C)'s 1 hour's work =1/12+1/20 = 2/15.

Therefore (3/20 + 2/15)= 17/60 part of work is completed in first 2 hrs.

17/60 part of work completed in ------- 2hrs.

1 part (full work) completed in ------- x hrs.

Now cross multiply => x= 2(60/17) = 7hrs.

Paridhi said:   1 decade ago
It written part filled in six hours then why is it multiplied by 3 and not six?

Vino said:   1 decade ago
Take LCM a, b, c = 180, tank capacity 180 liters.

a - 15 liter per hrs.
b - 12.
c - 9.

1hrs a+b = 27 liter.
1hrs a+c = 24 liter.

In choice more than 6 hrs.

= 27*4 = 108.
= 24*3 = 72.

Total 180 liters in 7 hrs.

Gnanamayil.k said:   1 decade ago
I feel its all lengthy calculation. Is there any simple shortcut method?

Potato singh said:   1 decade ago
Yes, take a bucket of 60 ltr capacity. Install 3 taps in your bathroom and get started.

Arun said:   1 decade ago
1 hr tank can fill 3/20 -> (1/12+1/15).

2nd hr tank can fill 3/20+2/15 = 17/60.

For 2 hr it fills 17/60 then for 1 hr it fills 17/120 -> (1/2*17/60).

Consider 17 table 17*6 = 102, so in six hours it it fills 102/120 and next hr B Pipe will be open and.

Fills as 102/120+3/20 = 1. So 7 hrs it will take.

Another way:

For 2 hrs it fills 17/60.

Consider next 2 hrs i.e. 4 hrs 2*17/60 = 34/60.

Consider next 2 hrs i.e 6 hrs 51/60 only 9 is less for 60 i.e to full.

So next 1 hr b pipe open 51/60+9/60 = 1.

Swetha said:   10 years ago
Please say short cut method for problem 14 it is length process.


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