Aptitude - Pipes and Cistern - Discussion
Discussion Forum : Pipes and Cistern - General Questions (Q.No. 12)
12.
A large tanker can be filled by two pipes A and B in 60 minutes and 40 minutes respectively. How many minutes will it take to fill the tanker from empty state if B is used for half the time and A and B fill it together for the other half?
Answer: Option
Explanation:
Part filled by (A + B) in 1 minute = | ![]() |
1 | + | 1 | ![]() |
= | 1 | . |
60 | 40 | 24 |
Suppose the tank is filled in x minutes.
Then, | x | ![]() |
1 | + | 1 | ![]() |
= 1 |
2 | 24 | 40 |
![]() |
x | x | 1 | = 1 |
2 | 15 |
x = 30 min.
Discussion:
51 comments Page 5 of 6.
Joy Prakesh said:
1 decade ago
Anyone can give any explanation of @Sri's comment?
Kumar said:
1 decade ago
Some one explain in more detailed manner.
Pavan said:
7 years ago
Very good explanation, Thank you @Ishan.
(1)
Santosh said:
7 years ago
The answer is 32. I agree with this.
(1)
Pratham said:
4 years ago
I agree The right answer is 32.
(14)
Raj karan said:
8 years ago
Well explained, thanks @Ayush.
Manasa said:
1 decade ago
Thanks ishan. Well explained.
Rashiqr Rahuman said:
6 years ago
Thanks @Sanjay Pahade.
Santhosh said:
1 decade ago
Thank You Pankaj
Santosh said:
6 years ago
Thanks @Viz.
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