Aptitude - Pipes and Cistern - Discussion

Discussion Forum : Pipes and Cistern - General Questions (Q.No. 12)
12.
A large tanker can be filled by two pipes A and B in 60 minutes and 40 minutes respectively. How many minutes will it take to fill the tanker from empty state if B is used for half the time and A and B fill it together for the other half?
15 min
20 min
27.5 min
30 min
Answer: Option
Explanation:

Part filled by (A + B) in 1 minute = 1 + 1 = 1 .
60 40 24

Suppose the tank is filled in x minutes.

Then, x 1 + 1 = 1
2 24 40

x x 1 = 1
2 15

x = 30 min.

Discussion:
51 comments Page 3 of 6.

M ramesh said:   1 decade ago
This problem solving easily this type.
Total time is = x.

b time = a+b time.
b one minute capacity = 2.5.
a+b one minute capacity = 2.5+1.66 = 4.16.

b+(a+b) = 1.
2.5*15m = 37.5.
4.16*15m = 62.5.

37.5+62.5 = 100, 15+15 = 30.

Shankar said:   9 years ago
Why can't it be In logical manner?

Half time of B + half of the time of (A + B) ==> 20+ (A+B) filling time.

A + B in 1 min = 1/24.

In x min = x/24 ==> 1/2 of Total Volume V.

So x = 12; Total time = 20 + 12 = 32.

Sree said:   1 decade ago
@suresh.

What you explained was very simple & easy to understand. But in the question its mentioned leaking the Time taken by pipe (B) & time taken by both pipes (A+B). So how can we subtract 50-20?

Madhu reddy said:   1 decade ago
So simple.

a =60; b= 40; a+b = 60*40/60+40 = 24 (formula).

Let's take tank capacity 2x min (i.e x+x).

x/40 + x/24 = 1 (full tank).

By solving, we get x = 15 min.

Therefore 2x = 2*15 = 30 min.

Praneeth Reddy said:   8 years ago
A's 1 minute work = 1/60.
B's 1 minute work = 1/40.

half d work done by B and remaining Half work by A&B.
= 1/2 [1/40] + 1/2 [1/24] {because 1/60+1/40=1/24}.
= 1/30.

Work done in 30 min.
(1)

Ayush said:   8 years ago
Here if you do it by simple LCM method u will get 32 answers but if you take 1 minute alternate for both u will get 30 answers as;

(3+5) = 2 minute cycle.
=120(lcm of 60 nd 40)/8 = 30minutes.

Suji said:   1 decade ago
Nothing to confuse last 2 lines of question is changed into eqn.

Given half time to fill. As we don't know min. We take as x ie. X/2.

A and B together+only B.

Viz said:   1 decade ago
x/2(only B) + x/2(A and B together) = 1.

x/2(1/40) + x/2 (1/60+1/40) = 1.

x/80 + x/2(5/120) = 1.

x/80 + 5x/240 = 1.

(3x+5x)/240 = 1.

8x = 240.

x=30 mins.

Salini said:   1 decade ago
@Madhu.

Here you are considering that B does half of work but in question they had mention only the half of time B does the work. Please clarify my doubt.

Suresh said:   1 decade ago
Here in this question they give a = 60, b = 40.

Then half of the b is = 20.

After half of the a and b that means a+b/2 = 60+40/2 = 50.

Then, 50-20 = 30.


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