Aptitude - Pipes and Cistern - Discussion

Discussion Forum : Pipes and Cistern - General Questions (Q.No. 3)
3.
A pump can fill a tank with water in 2 hours. Because of a leak, it took 2 hours to fill the tank. The leak can drain all the water of the tank in:
4 1 hours
3
7 hours
8 hours
14 hours
Answer: Option
Explanation:

Work done by the leak in 1 hour = 1 - 3 = 1 .
2 7 14

Leak will empty the tank in 14 hrs.

Discussion:
90 comments Page 6 of 9.

Raja said:   1 decade ago
@Sai.

Its actually 1/(7/3).

SAI TRIVENI said:   1 decade ago
As per question a pump can fill and due to leakage it took 1/3 of time extra.

As we can say {PUMP-(PUMP+LEAKAGE)== IF WE SIMPLEFY THIS == PUMP-PUMP-LEAKAGE THIS GIVE RESULT AS = -LEAKAGE.

I CAN'T UNDERSTAND WHY U REVERSED THE VALUE IT MUST BE 7/3 BUT U TOOK 3/7 HOW?

Vinay arora said:   1 decade ago
In 120 mints it complete = 1 tank
but it take 140 mints now so,
in 1 mint it fill =1/120
extra time it take be= 140-120= 20 mints
in 20 mint it fill= 20 * (1/120) =1/6
1/6 tank fill in 2 Hr 20 mint that is 7/3 so
1/6 of tank fill= 7/3
1 tank fill in= (7/3)*6= 14 hr
ok buddy......

Allhad said:   1 decade ago
To all who don't understand how 7/3.
Actually time given is 2hrs and 20min i.e. 2hrs+20min (1/3 hrs).

Raj said:   1 decade ago
It is very simple.

Pump takes 2hr to fill
& due to leakage it takes 7/3 hrs
calculate it in terms of 1 hr.
pump will fill 1/2 part of tank
& due to leakage 3/7 part of tank
so leakage in 1 hr will be
1/2 - 3/7 = 1/14 part,
so full tank will be empty in
14 hr.

Deepi said:   1 decade ago
A takes 2 hrs lets take as x
Leakage time lets y
2 1/3 hrs=7/3hrs

=> (x*y)/(y-x)=7/3
=> (2y)/(y-2)=7/3
=> 2y=(y-2)(7/3)
=> 2y=(7y/3)-14/3
=> -y/3=-14/3
=> y=14

Ashu said:   1 decade ago
@chakri

If you take 7/3 hrs to complete 1 job

Then, what length of job will you take to complete in 1 hour
( what you do here is...use reciprocal value when u shift the value)
that is
7/3=>1
1=>3/7

Sandeep said:   1 decade ago
Lets us simplify by doing it minute basis:.

Let the Volume be V without leak tank is filled in 120 min.

So, in 1 min = V/120.

With leak, = V/140.

Leak is withdrawing water per min = V/120 - V/140 = V/840.

i.e 840th part is filled in 1 min.

So the tank is filled in 840 min i.e. 14 hours.

----------------------------------------------------------------Hour Basis,

In 1 hour V/2 with leak, 3V/7.

Work by leak = V/2-3V/7 = V/14.

V = 14 h.

Chakri said:   1 decade ago
Please tell me why it's 7/3 changed into 3/7?

PGCR ( Sri Lanka) said:   1 decade ago
Just because of the leak it took 2 1/3 hours.
Normally it takes only 2 hours.
Hence,

1 1 1
- - - = -
2 X (2 1/3)


OR


1 1 1
- - - = -
2 (2 1/3) X


So, X = 14 hours.


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