Aptitude - Pipes and Cistern - Discussion

Discussion Forum : Pipes and Cistern - General Questions (Q.No. 3)
3.
A pump can fill a tank with water in 2 hours. Because of a leak, it took 2 hours to fill the tank. The leak can drain all the water of the tank in:
4 1 hours
3
7 hours
8 hours
14 hours
Answer: Option
Explanation:

Work done by the leak in 1 hour = 1 - 3 = 1 .
2 7 14

Leak will empty the tank in 14 hrs.

Discussion:
90 comments Page 5 of 9.

Jothigonzi said:   5 years ago
@Deepi.

Nice explanation and easier to understand. Thanks.

Reddy said:   5 years ago
How 3/7 with leakage? Explain, please.

SUDHARSHAN NAIDU said:   5 years ago
The efficiency of a pipe in 1 hour is 1/2 = 0.5lit/h.
The efficiency of a pipe with leakage 1/2.33 = 0.429,
The difference between 0.5 - 0.429 is 0.07.
The efficiency of a leak is 0.07lits/ hour.
So, check with an option in how many hours the 1-litre tank empty we get the answer.

Dhivyanisan said:   4 years ago
Time is taken by pump without leak = 2hrs.
Its discharge capacity says a= 1/2.
Time is taken by a pump with leak = 2 (1/3)hrs or 7/3 hrs.
It's discharge capacity say b= 1/(7/3) = 3/7.
So discharge capacity of the leak is a-b = 1/14.
Time taken by the leak to empty tank = 1/(1/14) = 14 hrs.

Messi said:   4 years ago
Thanks for explaining @Suresh.

Ashu said:   1 decade ago
PGCR great logic. What type of logic you used here?

Please explain.

MGH said:   1 decade ago
@Mohanpriya.

Why have we done the calculation till 140 mins?

Govindarajan said:   1 decade ago
20 mins extra for 2 hour i.e. 120 mins.

120 mins is first tank.

140 mins is second tank.

120/x = 140/20.

140/20*120 = 840 mins.

1 hour = 60 mins.

14 hours = 14 hours.

Mohanapriya said:   1 decade ago
2 hrs compose 120 mins.

But due to leak it takes 120+20 = 140 mins.

1st 2hr - 20 goes of [the amount has to be filled in 20 mins].

4nd hr - 40 mins.

6th hr - 60 mins.

8th hr - 80 mins.

10th hr - 100 mins.

12th hr - 120 mins.

14th hr - 140 mins.

And so it takes 14 hours to empty a full tank.

Abhilash said:   1 decade ago
Actually tank could have filled in 2 hr.

Part will be 1/2.

Let the time taken by the leakage is y.

Therefore, part is 1/y.

3/7 = (1/2-1/y) here 3/7 is the total time taken to fill the tank (in parts).

1/y = ((7-6))/14.

y = 14.


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