Aptitude - Pipes and Cistern - Discussion

At any time proportion of solution R is same with respect to other two solution,

In 1 minute A will drop =1/30.
" " "" " " B will drop =1/20.
" " " " " C will drop =1/10.

Multiplying 60 to each one,
A:B:C = 2:3:6.
Since solution R corresponds to C we have = 6/(6+3+2) = 6/11.

A - 30 min.
B - 20 min.
C - 10 min.
Now take LCM (30,20,10) = 60.

So,
A - 60/30 = 2 LTR.
B - 3LTR.
C - 6 LTR.

So TOTAL 2+3+6 = 11 LTR.
So proportion of C is 6/11.

So Simple.

@Lalitha

= 1/30+1/20+1/10
So L.C.M of 30,20,10=60
Then 1/30+1/20+1/10=2+3+6/60
=11/60
ok

Pipe A fills the tank in 30 min
in one min pipe A fills 1/30 of the tank
pipe B fills the tank in 20 min
in one min pipe B fills 1/20 of the tank
pipe C fills the tank in 10 min
in one min pipe C fills 1/10 of the tank
part of the tank filled when all the three pipes are opened for one min is {(1/30)+(1/20)+(1/10)}=11/60
the part of the tank filled when all three pipes are opened for
three min is =3*(11/60)=33/60=11/20
now the chemical solution R present after 3 min=3*(part of the tank filled by C for one min)
=3*1/10=3/10
propotion of sol R in the tank after 3min=(chemical soln r in the tank after 3 min)/(total chemical soln in the tank)
=(3/10)/(11/20)=(3*20)/(11*10)=60/110=6/11
hence the ans is 6/11

Hi,

Please any one check whether my solution is right?

'A' fills tank =30 mins.
'B' fills tank =20 mins.
'C'fills tank =10 mins.

So if we find the LCM for this means we'll assume it as our tanks capacity,

Here its LCM is 60
The tanks capacity is 60 litres

A' fills d tank= 2 lit/min
B' fills d tank=3 lit / min
C' fills d tank=6 lit / min

(A+B+C)'s fill d tank = 11 lit/min

A , B , C respectively discharge P,Q,R respectively

So C it self discharge 6/11 lit