Aptitude - Pipes and Cistern - Discussion
Discussion Forum : Pipes and Cistern - General Questions (Q.No. 1)
1.
Three pipes A, B and C can fill a tank from empty to full in 30 minutes, 20 minutes, and 10 minutes respectively. When the tank is empty, all the three pipes are opened. A, B and C discharge chemical solutions P,Q and R respectively. What is the proportion of the solution R in the liquid in the tank after 3 minutes?
Answer: Option
Explanation:
| Part filled by (A + B + C) in 3 minutes = 3 |  |
1 | + | 1 | + | 1 |  |
= | |
3 x | 11 | |
= | 11 | . |
| 30 | 20 | 10 | 60 | 20 |
| Part filled by C in 3 minutes = | 3 | . |
| 10 |
 Required ratio = |
|
3 | x | 20 | |
= | 6 | . |
| 10 | 11 | 11 |
Discussion:
78 comments Page 7 of 8.
Angel said:
2 decades ago
How 3/10 came ? Please explain it in detail.
Vinod said:
10 years ago
Please, anyone of you tell me How 11/20 is reciprocated?
Raji said:
10 years ago
You are right @Shakthi.
Roja said:
10 years ago
11/60 is the LCM.
Bindu said:
10 years ago
Is there any easy trick to solve this problem, Plese tell me.
Nishant said:
10 years ago
Why we reciprocal 11/20?
Please tell the answer.
Please tell the answer.
Sadia said:
10 years ago
Can anybody share the simple method for this question?
Drishti Anand said:
10 years ago
Why they took the reciprocal of 11/20 in final step?
Sujohn rayamajhi said:
1 decade ago
Why C's filling is counted twice? Once in total and then individually.
JISHNU said:
9 years ago
Regardless of the minutes the ratio will always the same,
i.e, the ratio is [1/10] / [(1/30) + (1/20) + (1/10)] = (1/10)/(11/60) = 6/11.
i.e, the ratio is [1/10] / [(1/30) + (1/20) + (1/10)] = (1/10)/(11/60) = 6/11.
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