Aptitude - Pipes and Cistern - Discussion
Discussion Forum : Pipes and Cistern - General Questions (Q.No. 1)
1.
Three pipes A, B and C can fill a tank from empty to full in 30 minutes, 20 minutes, and 10 minutes respectively. When the tank is empty, all the three pipes are opened. A, B and C discharge chemical solutions P,Q and R respectively. What is the proportion of the solution R in the liquid in the tank after 3 minutes?
Answer: Option
Explanation:
| Part filled by (A + B + C) in 3 minutes = 3 |  |
1 | + | 1 | + | 1 |  |
= | |
3 x | 11 | |
= | 11 | . |
| 30 | 20 | 10 | 60 | 20 |
| Part filled by C in 3 minutes = | 3 | . |
| 10 |
 Required ratio = |
|
3 | x | 20 | |
= | 6 | . |
| 10 | 11 | 11 |
Discussion:
75 comments Page 4 of 8.
Prabhas said:
8 years ago
3/10*20/11=6/11?
Plz explain.
Plz explain.
MrunalMehta said:
8 years ago
@Mohsin & @Prabhas.
The part filled by C in 3 mins is 3/10 and part filled by all three combined together is 11/20. To find the proportion of solution are we have to divide 3/10 by 11/20, thus multiplied by 20/11*.
If we divide a number say 25 by 5 we have 2 options.
I) 25/5 i.e- 5 or.
II) 25 x INVERSE OF 5 (I. E- 1/5) = 25x 1/5.
Both are one and the same. Hope this clears.
The part filled by C in 3 mins is 3/10 and part filled by all three combined together is 11/20. To find the proportion of solution are we have to divide 3/10 by 11/20, thus multiplied by 20/11*.
If we divide a number say 25 by 5 we have 2 options.
I) 25/5 i.e- 5 or.
II) 25 x INVERSE OF 5 (I. E- 1/5) = 25x 1/5.
Both are one and the same. Hope this clears.
Bibhuti Bhusan Swain said:
7 years ago
@Lalli.
When 1/30+1/20+1/10 add up they give 11/60.
When 1/30+1/20+1/10 add up they give 11/60.
Anitha said:
7 years ago
C spend max time 10 minutes.
So, 3/10 minutes.
(3/10)*(20/11).
6/11.
So, 3/10 minutes.
(3/10)*(20/11).
6/11.
Amit ravanak said:
7 years ago
How 6/11?
Please explain in detail.
Please explain in detail.
Guruprasad R said:
7 years ago
How 11/60? please explain.
Rohit said:
6 years ago
LCM of 20,30 and 60 are but ratio 3,2 and 1 and their lcm is 6 which is diveded as by 2,3,6 respectively. Now sum is 11 and after 3 minutes q {3} 3+3 =6 /11
Abey said:
6 years ago
How 3/10? Please explain.
Deepanshu Sharma said:
5 years ago
@Satya.
Initially, we calculate as per pipe and for total, we need to do reciprocal.
Initially, we calculate as per pipe and for total, we need to do reciprocal.
Sumanth Gowda said:
1 decade ago
Hey guys listen properly.
A part filled by 3 min
for a=1/30,b=1/20,c=1/20
first u add this tree and multiply by 3 min k then u'l get 11/20
discharge chemical solutions P,Q and R respectively its equal to A,Band C
observe carefully P=A,Q=B,R=C;
proportion of the solution R in the liquid in the tank after 3 minutes where 3min s nothing but 3(C).....3(1/10) ie 3/10
Now u got ans.
A part filled by 3 min
for a=1/30,b=1/20,c=1/20
first u add this tree and multiply by 3 min k then u'l get 11/20
discharge chemical solutions P,Q and R respectively its equal to A,Band C
observe carefully P=A,Q=B,R=C;
proportion of the solution R in the liquid in the tank after 3 minutes where 3min s nothing but 3(C).....3(1/10) ie 3/10
Now u got ans.
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