Aptitude - Pipes and Cistern - Discussion
Discussion Forum : Pipes and Cistern - General Questions (Q.No. 2)
2.
Pipes A and B can fill a tank in 5 and 6 hours respectively. Pipe C can empty it in 12 hours. If all the three pipes are opened together, then the tank will be filled in:
Answer: Option
Explanation:
| Net part filled in 1 hour |  |
1 | + | 1 | - | 1 |  |
= | 17 | . |
| 5 | 6 | 12 | 60 |
 The tank will be full in |
60 | hours i.e., 3 | 9 | hours. |
| 17 | 17 |
Discussion:
57 comments Page 4 of 6.
Ajmal said:
10 years ago
How 60/17 can write as 3*9/17?
(1)
Pranav Kumar said:
10 years ago
I didn't understand this problem and can some one make it clear.
Bijayalaxmi said:
10 years ago
Formula: xyz/yz+xz-xy.
Anita sahoo said:
10 years ago
@Subrat please tell me how C is 5?
Anita sahoo said:
10 years ago
1/5+1/6-1/12=17/60.
How it possible?
1/5+1/6-1/12=-1/20.
Why not? Please explain.
How it possible?
1/5+1/6-1/12=-1/20.
Why not? Please explain.
Aryan kanti said:
1 decade ago
How do we find the time taken?
Nelson said:
1 decade ago
@Sameera, the tank will be filled as you can see the rate of filling is more than the rate of emptying. If the tank can't be filled, then the math would have told us so.
Sameera said:
1 decade ago
Thanks manasa but I can't understand one point ie;c is used for emptying of tank & when a&b are used to filling of water so when we use the 3 pipes simultaneously then at any time or at any point the will not be FILL so how can we conclude with a simple answer.
SUBRAT KUMAR DHANI said:
1 decade ago
A PIPE - 5HRS.
B PIPE- 6HRS.
C PIPE - 12HRS TO EMPTY IN TANK, SO THAT,
A-5 B-6 C-12 (TOTAL L.C.M 60 UNIT TANK CAPACITY).
A-12UNIT, B-10UNIT ,C-5UNIT.
TOGETHER(A+B)-EMPTY(C) = 12+10-5 = 17.
TOTAL UNIT 60/17 = 3.52
B PIPE- 6HRS.
C PIPE - 12HRS TO EMPTY IN TANK, SO THAT,
A-5 B-6 C-12 (TOTAL L.C.M 60 UNIT TANK CAPACITY).
A-12UNIT, B-10UNIT ,C-5UNIT.
TOGETHER(A+B)-EMPTY(C) = 12+10-5 = 17.
TOTAL UNIT 60/17 = 3.52
(4)
Alka said:
1 decade ago
@Happy.
First of all take L.C.M of 5, 6, &12. Then divide this L.C.M with every numerator & multiply that value with denominator of same.
First of all take L.C.M of 5, 6, &12. Then divide this L.C.M with every numerator & multiply that value with denominator of same.
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