Aptitude - Pipes and Cistern - Discussion

Discussion Forum : Pipes and Cistern - General Questions (Q.No. 2)
2.
Pipes A and B can fill a tank in 5 and 6 hours respectively. Pipe C can empty it in 12 hours. If all the three pipes are opened together, then the tank will be filled in:
1 13 hours
17
2 8 hours
11
3 9 hours
17
4 1 hours
2
Answer: Option
Explanation:

Net part filled in 1 hour 1 + 1 - 1 = 17 .
5 6 12 60

The tank will be full in 60 hours i.e., 3 9 hours.
17 17

Discussion:
57 comments Page 5 of 6.

Kiran said:   1 decade ago
@kaveri

1/5+1/6+-1/12=

L.C.M of 5,6,12=60
So 1/5+1/6-1/12

12+10-5
--------------= 17
60 --------
60

Rohit said:   1 decade ago
Thanks neha.

Mageswari said:   1 decade ago
Thanks manasa your explanation is clear cut.

Divya said:   1 decade ago
Thanks manasa.

Rav said:   1 decade ago
Will it work in every case ?

Deepi said:   1 decade ago
Hi guys use this concepts to find the solution in easily
Concept 1:
A fill tank in x hrs and B fill in Y hrs and C in z hrs means together fill=?
A&B=X*y/x+y
let that A&B ans as p
then A,B&C=p*z/p+z
Concept 2:
A fill tank in x hrs and B empty in Y hrs then both together work how much time is to empty=?
=x*y/y-x

Neha said:   1 decade ago
(1/5 + 1/6 - 1/12) = (6+5/30 - 1/12)
= (11/30 -1/12)
= (132-30/360)
= (102/360)dividing numerator &denominator by 2
= (51/180)dividing numerator &denominator by 2
= (17/60)
(1)

Kaveri said:   1 decade ago
I can't understand how it is solved.

1/5+1/6-1/12 =17/60.

Please help.

Happy said:   1 decade ago
I can't understand how it is solved.

1/5+1/6-1/12 =17/60.

Please help.

Preeti said:   1 decade ago
Thanks Manasa. I got it clearly.
(1)


Post your comments here:

Your comments will be displayed after verification.